问题描述
在通过此代码运行文本之后:
import re
def text_manipulator(text):
paras = re.split('\n|\n ',text)
item_number = 0
for item in paras:
item_replace = re.split('(?<=[.!?]) +',item)
paras[item_number] = item_replace
item_number += 1
fixed_paras = [x for x in paras if x]
return fixed_paras
我剩下这个了。
[["Not a postal worker,but I'm good friends with the one on my route,"],[''],['He has helped me through some tough times (just a nice guy to talk to)'],['I often offer him a cold gallon of water or a energy drink,he seems to really enjoy.','He is a real down to earth guy.']]
该如何处理?
[["Not a postal worker,'He is a real down to earth guy.']]
预先感谢
解决方法
根据any(iterable)
的文档:
如果iterable的任何元素为true,则返回
True
。如果iterable为空,则返回False
。
因此,当将字符串列表传递给Any
时,如果列表中的所有元素都是空字符串,则它将返回False
,因为Empty String等效于False
。 / p>
因此,在您的代码中,将第二行替换为:
fixed_paras = [x for x in paras if any(x)]
也将删除具有空字符串的列表。
注意:该答案基于juanpa.arrivillaga的评论