javafx上的TableView显示空行

问题描述

我想创建一个方法，该方法将在borderpane中返回一个表，但是我得到了空表，并且它的标签显示在GUI上。这是代码：

@Override
public void start(Stage stage) throws Exception {
    borderpane border = new borderpane();
    VBox cBox = addCBox(); //center Box
    border.setCenter(cBox);
  
    Scene scene = new Scene(border,600,650);
    stage.setTitle("Test Project"); // Set the stage title
    stage.setScene(scene); // Place the scene in the stage
    stage.show(); // display the stage
}

这是我通过遵循文档创建表数据和方法的方式：

private final TableView<Doctor> table = new TableView<>();
    private final ObservableList<Doctor> data = FXCollections.observableArrayList(
        new Doctor("196","Daniel LW","Cardiologists","9-6","MBBCh"),new Doctor("197","James DN","Anesthesiologists","4-9","LRCP"),new Doctor("199","Chales AK","Dermatologists","6-12","BSc")
    );

    public static void main(String[] args) {
        launch(args);
    }

    public VBox addCBox() {
        final Label label = new Label("Doctor List");
        label.setFont(new Font("Arial",20));
        table.setEditable(true);
        
        TableColumn<Doctor,String> col1 = new TableColumn<Doctor,String>("ID");
        col1.setMinWidth(30);
        col1.setMaxWidth(60);
        col1.setCellValueFactory(new PropertyValueFactory<>("id"));
        
        TableColumn<Doctor,String> col2 = new TableColumn<Doctor,String>("NAME");
        col2.setMinWidth(100);
        col2.setCellValueFactory(new PropertyValueFactory<>("name"));

        table.setItems(data);
        table.getColumns().addAll(col1,col2);
        // the above line prompt me warning message,but although I use:
        // table.getColumns().add(col1); table.getColumns().add(col2);
        // the rows of data still not visible
        // I only get the empty clickable rows

        final VBox cBox = new VBox();
        cBox.setPadding(new Insets(10,20,10,10));
        cBox.getChildren().addAll(label,table);
        
        return cBox;
    }

这是我创建的类的简化版本。有设置者和获取者。

public static class Doctor {
    private SimpleStringProperty id,name,specialist,workTime,qualification;
        
    public Doctor(String id,String name,String specialist,String workTime,String qualification) {
        this.id = new SimpleStringProperty(id);
        this.name = new SimpleStringProperty(name);
        this.specialist = new SimpleStringProperty(specialist);
        this.workTime = new SimpleStringProperty(workTime);
        this.qualification = new SimpleStringProperty(qualification);
    }
}

解决方法

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java java javafx tableview tableview