带有左联接并在where子句中组合AND和OR的mysql查询 table1： table2：

编程问答 2022-08-16

问题描述

我有两个表，table1和table2，分别是LEFT JOIN。在两个表上都应该有一个AND和OR条件组合的查询。在单个查询中更可取。我知道我可以执行几个查询并与id的数组相交（使用PHP），但是...

table1：

id     email    status
1      a@one    1
2               1
3      b@two    1
4      c@three  0
5      d@four   1
6      e@five   1

table2：

ix   t_id    type     value
1    1       1        Miller
2    1       2        10001
3    1       3        x
4    1       5        y
5    2       1        Miller
6    2       2        20002
7    2       3        x
8    3       1        Muller
9    3       2        10002
10   3       5        x
11   4       1        Mayer
12   4       2        10002
13   4       3        x
14   5       1        Moore
15   5       2        10234
16   6       1        Zlo
17   6       2        12345
18   6       3        x
19   6       5        x

我需要一个查询，在这里我想要所有活动人员（status=1）的所有ID，其中要有一封电子邮件（都在table1中），该人员的姓名（类型1）必须以M AND的邮政编码（类型2）必须以1 AND开头，它们的类型3是x OR类型5是x（均在table2中）。 / p>

如果没有EITHER type = 3 OR type = 5条目，则不应返回ID。

如果type = 3或type = 5不应返回id，但两个值都不为x

在我的示例中：

t_id 4 (Mayer) ist not active,so he should not be in the result
t_id 2 (Miller) has no email,so he should not be in the result
t_id 5 (Moore) does not have type 3 and does not have type 5 so he should not be in the result
t_id 6 (Zlo) the name does not begin with M so he should not be in the result

我设法写了这样的东西，但它在所有零行都不起作用：

SELECT id 
FROM table2 
    LEFT JOIN table1 ON (t_id = id WHERE email LIKE '%@%' AND status = '1') 
WHERE (type = 1 and value LIKE 'M%') 
AND (type = 2 AND value LIKE '1%') 
AND ((type = 3 AND value = 'x') OR (type = 5 and value = 'x'))

任何帮助将不胜感激！

谢谢RiggsFolly

有了不错的帮助之后，它就会（并且可以正常工作）

SELECT id 
FROM table2 
LEFT JOIN table1 ON table2.userid = table1.id 
AND status = 1 AND email LIKE '%@%' 
WHERE ( 
(type = 3 AND value = 'X') 
OR (type = 5 AND value = 'X') 
)

table2的附加条件无法集成，将成为单独的查询：

SELECT id 
FROM table2 
LEFT JOIN table1 ON table2.userid = table1.id 
AND status = 1 AND email LIKE '%@%' WHERE (type = 1 AND value LIKE 'G%')

和

SELECT id 
FROM table2 
LEFT JOIN table1 ON table2.userid = table1.id 
AND status = 1 AND email LIKE '%@%' WHERE (type = 2 AND value LIKE '1%')

解决方法

具体类型不能为1、2和3，但可以为1、2或3 

SELECT id 
FROM table2 t2
    LEFT JOIN table1 t1 ON t2.t_id = t1.id AND status = '1'
WHERE t1.email LIKE '%@%'
AND (
        (t2.type = 1 and t2.value LIKE 'M%') 
    OR  (t2.type = 2 AND t2.value LIKE '1%') 
    OR  (t2.type = IN(3,5) AND t2.value = 'x')
    )
combinationsmysqlwhere-clause