使用try-with-resources重写此代码

问题描述

此代码用于通过Java序列化复制实例。它使用传统的try-catch-finally编写方法。可以更改为 try-with-resources 形式吗？（代码中的 DeepConcretePrototype 是普通的Java对象）

    /**
     * Clone an instance through java serialization
     * @return
     */
    public DeepConcretePrototype deepCloneBySerializable() {
        DeepConcretePrototype clone = null;
        ByteArrayOutputStream byteArrayOutputStream = null;
        ObjectOutputStream objectOutputStream = null;
        ByteArrayInputStream byteArrayInputStream = null;
        ObjectInputStream objectInputStream = null;
        try {
            //Output an instance to memory
            byteArrayOutputStream = new ByteArrayOutputStream();
            objectOutputStream = new ObjectOutputStream(byteArrayOutputStream);
            objectOutputStream.writeObject(this);
            objectOutputStream.flush();
            //Read instance from memory
            byteArrayInputStream = new ByteArrayInputStream(byteArrayOutputStream.toByteArray());
            objectInputStream = new ObjectInputStream(byteArrayInputStream);
            clone = (DeepConcretePrototype)objectInputStream.readObject();
        } catch (IOException e) {
            e.printStackTrace();
        } catch (ClassNotFoundException e) {
            e.printStackTrace();
        } finally {
            if (byteArrayOutputStream != null) {
                try {
                    byteArrayOutputStream.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            if (objectOutputStream != null) {
                try {
                    objectOutputStream.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            if (byteArrayInputStream != null) {
                try {
                    byteArrayInputStream.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            if (objectInputStream != null) {
                try {
                    objectInputStream.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
        return clone;
    }

解决方法

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