Winapi窗口在C中没有响应

问题描述

我一直在尝试使用WinAPI创建一个简单的窗口,它会编译并链接一些警告,当我打开程序时,该窗口会显示出来,但是当我尝试与之交互时,会播放一个Windows警告声并它不允许我使用该窗口,甚至不能将其关闭,而必须使用任务管理器。

要编译它,我在命令行中使用Microsoft的“ cl.exe”:

cl /c window.c

并且警告是:

window.c(39): warning C4133: 'function': incompatible types,from 'LPSTR' to 'HINSTANCE'
window.c(40): warning C4133: 'function': incompatible types,from 'LPSTR' to 'HINSTANCE'
window.c(41): warning C4047: '=': 'HBrush' differs in levels of indirection from 'int'

链接,我在命令行上使用crinkler

crinkler /NODEFAULTLIB /ENTRY:main /SUSBYstem:WINDOWS /TINYHEADER /TINYIMPORT /OUT:c.exe window.obj kernel32.lib user32.lib

警告是:

: warning LNK: Entry point not at start of section,jump necessary

我正在使用的代码是:

#include <windows.h>

#define WINDOW_STYLE        WS_VISIBLE+WS_OVERLAPPEDWINDOW-WS_THICKFRAME-WS_MAXIMIZE
#define WINDOW_WIDTH        640
#define WINDOW_HEIGHT       480

static const char* window_name = "My Window";
RECT window_rect = {0,WINDOW_HEIGHT,WINDOW_WIDTH};

LRESULT CALLBACK WindowProc(HWND hwnd,UINT uMsg,WParaM wParam,LParaM lParam)
{
    switch(uMsg)
    {
    case WM_CLOSE:
        PostQuitMessage(0);
        break;
    case WM_DESTROY:
        PostQuitMessage(0);
        break;
    }

    return DefWindowProcA(hwnd,uMsg,wParam,lParam);
}

int main()
{
    int ret = 0;
    HMODULE instance = GetModuleHandleA(NULL);

    AdjustwindowRect(&window_rect,WINDOW_STYLE,FALSE);

    WNDCLASSEXA window_class;
    window_class.cbSize = 48;
    window_class.style = CS_OWNDC|CS_HREDRAW|CS_VREDRAW;
    window_class.lpfnWndProc = WindowProc;
    window_class.cbClsExtra = 0;
    window_class.cbWndExtra = 0;
    window_class.hInstance = instance;
    window_class.hIcon = LoadIconA(IDI_APPLICATION,0);
    window_class.hCursor = LoadCursorA(IDI_APPLICATION,0);
    window_class.hbrBackground = COLOR_WINDOW;
    window_class.lpszMenuName = 0;
    window_class.lpszClassName = window_name;
    window_class.hIconSm = 0;

    if (RegisterClassExA(&window_class)) {

        HWND window = CreateWindowExA(
            0,window_name,CW_USEDEFAULT,window_rect.right - window_rect.left,window_rect.bottom - window_rect.top,instance,NULL);

        ShowWindow(window,SW_SHOW);
        UpdateWindow(window);

        MSG msg;

        while(1)
        {
            if (PeekMessageA(&msg,PM_REMOVE)) {
                if (msg.message == WM_QUIT) {
                    ExitProcess(0);
                    break;
                } else {
                    TranslateMessage(&msg);
                    dispatchMessage(&msg);
                }
            }
        }
    } else {
        ret = 1;
    }

    ExitProcess(0);

    return ret;
}

有人知道如何解决吗?谢谢。

解决方法

以下行不执行您认为的操作:

#define WINDOW_STYLE WS_VISIBLE+WS_OVERLAPPEDWINDOW-WS_THICKFRAME-WS_MAXIMIZE

虽然有点普遍,有时甚至会产生正确的值,但这是实现位操作的一种非常脆弱的方法。在这种情况下,表达式扩展为:

0x10000000L + 0x00CF0000L - 0x00040000L - 0x01000000L

这将产生值0xFFCB0000L 1 (由于不小心使用了WS_MAXIMIZE而不是WS_MAXIMIZEBOX)。这将转换为具有以下样式的窗口:

  • WS_POPUP
  • WS_CHILD(请注意,它已经与WS_POPUP互斥)
  • WS_ICONIC
  • WS_VISIBLE
  • WS_DISABLED
  • ...

documented

WS_DISABLED:该窗口最初被禁用。 已禁用的窗口无法接收来自用户的输入。要在创建窗口后更改此设置,请使用EnableWindow功能。

这说明了为什么无法与窗口进行交互。修复很简单:使用按位运算符而不是算术运算符进行位操作:

#define WINDOW_STYLE (WS_VISIBLE | WS_OVERLAPPEDWINDOW & ~WS_THICKFRAME & ~WS_MAXIMIZE)

1 事实上,没有定义有符号溢出的行为。