问题描述
我有一个色彩大师作为下面的列表
master <- list("Beige" = c("light brown","light golden","skin"),"off-white" = c("off white","cream","light cream","dirty white"),"Metallic" = c("steel","silver"),"Multi-colored" = c("multi color","mixed colors","mix","rainbow"),"Purple" = c("lavender","grape","jam","raisin","plum","magenta"),"Red" = c("cranberry","strawberry","raspberry","dark cherry","cherry","rosered"),"Turquoise" = c("aqua marine","jade green"),"Yellow" = c("fresh lime")
)
这是我拥有的datframe列
df$color <- c('multi color','purple','steel','metallic','off white','raisin','strawberry','magenta','skin','Beige','Jade Green','cream','multi-colored','offwhite','rosered',"light cream")
现在我要检查column中存在的值是否与list key相同或与list values相同
ex ：
1）如果df列的值首先为off white，则应查看列表键（如果存在）为Beige,off-white,Metallic...而不是获取值
2）如果其中一个键值是light cream，它还应该查看这些键具有的所有值，而不是应将其视为off-white
3）没有大小写敏感的问题，例如OffWhITe == offwhite或空格问题，例如off white==offwhite
输出
这应该是预期的输出
df$output <- c("Multi-colored","Purple","Metallic","off-white","Red","Beige","Turquoise","Multi-colored","off-white")
编辑
此c("multi color","rainbow","multicolored","MultI-cOlored","multi-colored","MultiColORed","Multi-colored")中的任何值都应视为Multi-colored
解决方法
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