AWS SAM启动本地api返回“功能名称为必需”错误

编程问答 2022-08-15

问题描述

我们正在使用CDK来构建我们的基础结构配置。此外，如果有帮助，我可以使用template.yml为SAM创建cdk synth <stack_name> --no-staging > template.yml。我正在使用AWS Toolkit在Intellij上调用/调试我的lambda函数，效果很好。但是，如果我在终端上运行sam local start-api并向我的一个函数发送请求，则它将返回一个带有stacktrace的错误； 

Traceback (most recent call last):
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py",line 2317,in wsgi_app
    response = self.full_dispatch_request()
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py",line 1840,in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py",line 1743,in handle_user_exception
    reraise(exc_type,exc_value,tb)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/_compat.py",line 36,in reraise
    raise value
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py",line 1838,in full_dispatch_request
    rv = self.dispatch_request()
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/flask/app.py",line 1824,in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/samcli/local/apigw/local_apigw_service.py",line 203,in _request_handler
    self.lambda_runner.invoke(route.function_name,event,stdout=stdout_stream_writer,stderr=self.stderr)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/samcli/commands/local/lib/local_lambda.py",line 84,in invoke
    function = self.provider.get(function_name)
  File "/usr/local/Cellar/aws-sam-cli/0.53.0/libexec/lib/python3.7/site-packages/samcli/lib/providers/sam_function_provider.py",line 65,in get
    raise ValueError("Function name is required")
ValueError: Function name is required

这是我运行的命令

sam local start-api --env-vars env.json --docker-network test

给出输出

Mounting None at http://127.0.0.1:3000/v1 [GET,OPTIONS,POST]
Mounting None at http://127.0.0.1:3000/v1/user [GET,POST]
You can Now browse to the above endpoints to invoke your functions. You do not need to restart/reload SAM CLI while working on your functions,changes will be reflected instantly/automatically. You only need to restart SAM CLI if you update your AWS SAM template
2020-08-22 16:32:46  * Running on http://127.0.0.1:3000/ (Press CTRL+C to quit)
2020-08-22 16:33:03 Exception on /v1/user [OPTIONS]

这是我用作函数环境变量的env.json 

{
  "tenantGetV1Function54F63CB9": {
    "db": "alpha","connectionString": "mongodb://mongo"
  },"tenantPostV1FunctionA56822D0": {
    "db": "alpha","userGetV1Function7E6E55C2": {
    "db": "alpha","userPostV1FunctionEB035EB0": {
    "db": "alpha","connectionString": "mongodb://mongo"
  }
}

我也在macOS操作系统上运行Docker Desktop。

编辑：在这里，您可以找到简化的template.yml，它只有一个端点（一个函数定义），用于tenantGetV1Function54F63CB9函数。它将映射到GET / v1端点。我不想包含4个函数的整个模板，这使大约一千行.yml代码成为可能。

https://gist.github.com/flexelem/d887136484d508e313e0a745c30a2d97

解决方法

如果我通过传递LambdaIntegration实例而不是CDK中的Function实例来创建Alias，问题就解决了。因此，我们正在创建lambda和别名。然后，我们将别名从Api Gateway传递到其关联的Resource实例。

这是创建方式； 

Function tenantGetV1Function = Function.Builder.create(this,"tenantGetV1Function")
    .role(roleLambda)
    .runtime(Runtime.JAVA_8)
    .code(lambdaCode)
    .handler("com.yolda.tenant.lambda.GetTenantHandler::handleRequest")
    .memorySize(512)
    .timeout(Duration.minutes(1))
    .environment(environment)
    .description(Instant.now().toString())
    .build();

Alias tenantGetV1Alias = Alias.Builder.create(this,"tenantGetV1Alias")
    .aliasName("live")
    .version(tenantAdminGetV1Function.getCurrentVersion())
    .provisionedConcurrentExecutions(provisionedConcurrency)
    .build();

Resource v1Resource = v1Resource.addResource("{tenantId}");
v1Resource.addMethod("GET",LambdaIntegration.Builder.create(tenantGetV1Alias).build(),options);

如果我将tenantGetV1Alias替换为tenantGetV1Function，那么sam build命令将成功构建所有使sam local start-api旋转的功能。

Resource v1Resource = v1Resource.addResource("{tenantId}");
v1Resource.addMethod("GET",LambdaIntegration.Builder.create(tenantGetV1Function).build(),options);

以某种方式，如果我们分配了别名，SAM将无法从CloudFormation模板获取函数名称属性。

amazon-web-servicesaws-samaws-sam-cli