java.lang.AssertionError：有一个值列表，但不是期望的单个值

问题描述

要在Spring Boot应用程序中实现Java单元测试用例。

当我使用Java单元测试框架Junit 5匹配预期数据和实际数据时，出现此错误。

这是我实现的代码，

    @Test
    public void testListAddress() throws Exception {

        listAddress.add(new Address(1L,"road 89","Dhaka","Manikgonj1","1800"));
        listAddress.add(new Address(2L,"road 88","Dhaka1","Manikgonj2","1801"));

        Mockito.when(addressServiceImpl.findAllAddresses()).thenReturn(listAddress);
        String url = "/api/v1/address";
        MockHttpServletRequestBuilder builder = mockmvcRequestBuilders.get(url);
        ResultMatcher ok = mockmvcResultMatchers.status().isOk();
        final ObjectMapper objectMapper = new ObjectMapper();

        String expectedJsonResponse = objectMapper.writeValueAsstring(listAddress);

        ResultActions mvcResult = (ResultActions) this.mockmvc.perform(builder).andExpect(ok)
                .andExpect(mockmvcResultMatchers.jsonPath("$.data").value(expectedJsonResponse));

    }

我的端点结果如下：

{ 
"status":true,"message":"Address record lists!!","data":[
       {"id":1,"street":"road 89","city":"Dhaka","state":"Manikgonj1","zip":"1800"},{"id":2,"street":"road 88","city":"Dhaka1","state":"Manikgonj2","zip":"1801"}
    ]
}

堆栈跟踪：

   java.lang.AssertionError: Got a list of values

    [{"id":1,"zip":"1801"}]

     instead of the expected single value

     [{"id":1,"zip":"1801"}]

解决方法

你可以这样做：

import net.minidev.json.JSONObject;
import net.minidev.json.parser.JSONParser;
import com.fasterxml.jackson.databind.ObjectMapper;

...

listAddress.add(new Address(1L,"road 89","Dhaka","Manikgonj1","1800"));
listAddress.add(new Address(2L,"road 88","Dhaka1","Manikgonj2","1801"));

JSONParser jsonParser= new JSONParser(JSONParser.DEFAULT_PERMISSIVE_MODE);
ObjectMapper objectMapper = new ObjectMapper();

JSONArray listJson = (JSONArray) jsonParser.parse(objectMapper.writeValueAsString(listAddress));

ResultActions mvcResult = (ResultActions) this
.mockMvc
.perform(builder)
.andExpect(ok)
.andExpect(MockMvcResultMatchers.jsonPath("$.data").value(Matchers.containsInAnyOrder(listJson.toArray())));