如何在php中一行更新多个数据？

问题描述

我已经编写了一些代码，我需要登录的用户来更新其详细信息。当用户单击“更新”按钮时，只有一个字段正在更新数据，其余字段则没有。我有6个字段需要更新，一个字段运行良好，而其他5个字段却没有。我不确定下面的代码在哪里错误：

<?PHP

//all errors
ini_set('display_errors',1);
ini_set('display_startup_errors',1);
error_reporting(E_ALL);



// Initialize the session
session_start();
 
// Check if the user is logged in,otherwise redirect to login page
if(!isset($_SESSION["loggedin"]) || $_SESSION["loggedin"] !== true){
    header("location: login.PHP");
    exit;
}
 
// Include config file
require_once "config.PHP";
 
// Define variables and initialize with empty values
$investment = $cleared = $balance = $refnumber = $refbalance = $monthgain = "";
$investment_err = $cleared_err = $balance_err = $refnumber_err = $refbalance_err = $monthgain_err = "";
 
// Processing form data when form is submitted
if($_SERVER["REQUEST_METHOD"] == "POST"){
 
    // Validate fields
    if(empty(trim($_POST["investment"]))){
        $investment_err = "Iv error";     
    }if(empty(trim($_POST["cleared"]))){
        $cleared_err = "Cleared error";     
    }if(empty(trim($_POST["balance"]))){
        $balance_err = "Balance error";     
    }if(empty(trim($_POST["refnumber"]))){
        $refnumber_err = "Ref num error";     
    }if(empty(trim($_POST["refbalance"]))){
        $refbalance_err = "Ref bal error";     
    }if(empty(trim($_POST["monthgain"]))){
        $monthgain_err = "Monthgain error";     
    } else{
        $investment = trim($_POST["investment"]);
        $cleared = trim($_POST["cleared"]);
        $balance = trim($_POST["balance"]);
        $refnumber = trim($_POST["refnumber"]);
        $refbalance = trim($_POST["refbalance"]);
        $monthgain = trim($_POST["monthgain"]);
    }
        
    // Check input errors before updating the database
    if(empty($investment_err) && empty($cleared_err) && empty($balance_err) && empty($refnumber_err) && empty($refbalance_err) && empty($monthgain_err)){
        // Prepare an update statement
        $sql = "UPDATE users SET investment = ?  WHERE id = ?";
        
        if($stmt = MysqLi_prepare($link,$sql)){
            // Bind variables to the prepared statement as parameters
            MysqLi_stmt_bind_param($stmt,"si",$param_investment,$param_id);
            
            // Set parameters
            $param_investment = $investment;
            $param_cleared = $cleared;
            $param_balance = $balance;
            $param_refnumber = $refnumber;
            $param_refbalance = $refbalance;
            $param_monthgain = $monthgain;
            $param_id = $_SESSION["id"];
            
            // Attempt to execute the prepared statement
            if(MysqLi_stmt_execute($stmt)){
                // data updated successfully. Destroy the close page,and redirect to dashboard page
                header("location: ../dashboard.PHP");
                exit();
            } else{
                echo "Oops! Something went wrong. Please try again later.";
            }

            // Close statement
            MysqLi_stmt_close($stmt);
        }
    }
    
    // Close connection
    MysqLi_close($link);
}
?>

名称为投资的字段是唯一的更新。看截图 here

标有 X 的字段是我的问题！ 我的代码有什么问题？

解决方法

尝试这样做

css-1dbjc4n

,

您将需要看起来像这样的SQL才能通过单个查询更新多个列。

UPDATE users 
   SET investment = ?,cleared = ?,whatever = ?,whatelse = ?
  WHERE id = ?";

当然，请使用表中的实际列名。