Knex.js：用'where'子句连接'select'

问题描述

我尝试为此SQL查询创建knex查询：

SELECT
    *
FROM
    ad AS a
LEFT JOIN ad_file AS af ON
    af.ad_id = a.id
    AND af.file_id = (
    SELECT
        MIN(file_id)
    FROM
        ad_file AS afmin
    WHERE
        afmin .ad_id = a.id )

这是我的JS代码：

const trx = await knex.transaction();

const query = trx({a: "ad"});
const fileMin = trx({afm: "ad_file"});
fileMin.min("file_id");
fileMin.where("afm.ad_id",knex.raw("`a`.`id`"));

query.leftOuterJoin({af: "ad_file"},function () {
    this.on("a.id","af.ad_id");
    this.on("af.file_id",fileMin);
});

但是最后我有错误的SQL查询：

select
    *
from
    `ad` as `a`
left outer join `ad_file` as `af` on
    `a`.`id` = `af`.`ad_id`
    and `af`.`file_id` =
select
    min(`file_id`)
from
    `ad_file` as `afm`
where
    `afm`.`ad_id` = `a`.`id`

如何为SELECT MIN(file_id) FROM ... WHERE添加括号？

解决方法

这是我自己的解决方案：

query.leftOuterJoin({af: "ad_file"},function () {
    this.on("a.id","af.ad_id");
    this.on("af.file_id",trx.raw("?",[fileMin]));
});