如何使用右联接在Sybase中联接两个查询？

问题描述

在合并两个查询时遇到问题。有人可以检查我的代码吗？

tx_plans
provider_ids
提供者
ng_rest_prod
保险
invis_ortho_codes
thirds_implants
next_visit

        SELECT
          b.patient_id,LIST(a.service_code,',' ORDER BY a.service_code) AS tx_plans,b.provider_id AS provider_ids,(d.last_name + ',' + d.first_name) AS providers,'' AS ng_rest_prod,NULL AS insurance,'' AS invis_ortho_codes,'' AS thirds_implants,NULL AS next_visit
        FROM 
          transactions_header a 
          INNER JOIN transactions_detail b 
            ON a.tran_num = b.tran_num
          INNER JOIN 
          (
            SELECT  
              SUBSTRING(row_value,CHARINDEX('_',row_value)) AS tran_num,SUBSTRING(row_value,row_value)+1,LENGTH(row_value)) AS eod_date
            FROM sa_split_list('914561_2020-08-03,914562_2020-08-03,914563_2020-08-03,914564_2020-08-03,914565_2020-08-03')
          ) c 
            ON a.tran_num = c.tran_num
                    INNER JOIN provider d 
            ON b.provider_id = d.provider_id
        WHERE 1 = 1 
          AND a.impacts = 'P'
          AND eod_date BETWEEN DATEFORMAT('2020-08-24 00:00:00','YYYY-MM-01') AND '2020-08-24 00:00:00'
        GROUP BY b.patient_id,b.provider_id,providers

第二个查询应显示新的患者数据

patient_id
病人姓名
年龄

       SELECT 
          b.patient_id,' + d.first_name) AS patient_name,FLOOR(DATEDIFF(DAY,d.birth_date,TODAY(*))/365) AS age
        FROM
          transactions_header a 
          INNER JOIN transactions_detail b 
          ON a.tran_num = b.tran_num 
                    INNER JOIN 
          (
            SELECT  
              SUBSTRING(row_value,914565_2020-08-03')
          ) c 
          ON a.tran_num = c.tran_num
        INNER JOIN patient d
          ON b.patient_id = d.patient_id
        WHERE a.impacts = 'P'
          AND eod_date BETWEEN DATEFORMAT('2020-08-24 00:00:00','YYYY-MM-01') AND '2020-08-24 00:00:00'

                    AND d.first_visit_date BETWEEN DATEFORMAT('2020-08-24 00:00:00','YYYY-mm-01') AND '2020-08-24 00:00:00'
          AND a.tran_date = d.first_visit_date


        GROUP BY b.patient_id,patient_name,d.birth_date.

查询的输出应为新患者及其数据。

它返回Invalid expression near 'b.provider_id = d.provider_id'

这是我实现的代码

    SELECT
      b.patient_id,b.patient_name AS patient_name,b.age AS age,LIST(@R_404_6422@TINCT(a.tx_plans)) AS tx_plans,LIST(
        @R_404_6422@TINCT(
            CASE
              WHEN a.provider_ids IS NOT NULL
              THEN a.provider_ids
              ELSE ''
            END
          )
        ) AS provider_ids,LIST(
        @R_404_6422@TINCT(
            CASE
              WHEN a.providers IS NOT NULL
              THEN a.providers
              ELSE ''
            END
          )
        ) AS providers,SUM(ng_rest_prod) AS ng_rest_prod,LIST(a.insurance,' ORDER BY a.insurance) AS insurance,LIST(@R_404_6422@TINCT(a.invis_ortho_codes)) AS invis_ortho_codes,LIST(@R_404_6422@TINCT(a.thirds_implants)) AS thirds_implants,LIST(a.next_visit) AS next_visit
    FROM
      (
        SELECT
          b.patient_id,providers
      ) AS a 

      RIGHT JOIN 
      (
        SELECT 
          b.patient_id,'YYYY-MM-01') AND '2020-08-24 00:00:00'
          
                    AND d.first_visit_date BETWEEN DATEFORMAT('2020-08-24 00:00:00','YYYY-mm-01') AND '2020-08-24 00:00:00'
          AND a.tran_date = d.first_visit_date
           
                               
        GROUP BY b.patient_id,d.birth_date
      ) b
        ON a.patient_id = b.patient_id
  GROUP BY b.patient_id,age

解决方法

暂无找到可以解决该程序问题的有效方法，小编努力寻找整理中！

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