问题描述
我是tensorflow的新手,我正在制作一个可以进行乘法运算的AI,
我需要使它能够使我的模型将列表作为输入。
这是我的代码:
import tensorflow as tf
import numpy as np
import matplotlib.pyplot as plt
multiplication_q = np.array([[10,10],[1,1],[2,2],[0,0],[3,3],[4,4],[5,5],[6,6],[7,7],[8,8],[9,9],[11,[27,[30,[17,22],[20,13],[21,[19,24],19],11],15],12],[15,[18,[49,[12,4]],dtype=object)
multiplication_a = np.array([100,1,4,9,16,25,36,49,64,96,110,60,12,374,104,84,456,209,20,121,15,24,45,343,35,48],dtype=float)
model = tf.keras.Sequential([
tf.keras.layers.Dense(units=4,input_shape=[1]),tf.keras.layers.Dense(units=4),tf.keras.layers.Dense(units=1)
])
model.compile(loss='mean_squared_error',optimizer=tf.keras.optimizers.Adam(0.1))
history = model.fit(multiplication_q,multiplication_a,epochs=750,verbose=False)
print(model.predict([4,5]))
,这是错误消息:
ValueError: in user code:
/usr/local/lib/python3.6/dist-packages/tensorflow/python/keras/engine/training.py:806 train_function *
return step_function(self,iterator)
/usr/local/lib/python3.6/dist-packages/tensorflow/python/keras/engine/training.py:796 step_function **
outputs = model.distribute_strategy.run(run_step,args=(data,))
/usr/local/lib/python3.6/dist-packages/tensorflow/python/distribute/distribute_lib.py:1211 run
return self._extended.call_for_each_replica(fn,args=args,kwargs=kwargs)
/usr/local/lib/python3.6/dist-packages/tensorflow/python/distribute/distribute_lib.py:2585 call_for_each_replica
return self._call_for_each_replica(fn,args,kwargs)
/usr/local/lib/python3.6/dist-packages/tensorflow/python/distribute/distribute_lib.py:2945 _call_for_each_replica
return fn(*args,**kwargs)
/usr/local/lib/python3.6/dist-packages/tensorflow/python/keras/engine/training.py:789 run_step **
outputs = model.train_step(data)
/usr/local/lib/python3.6/dist-packages/tensorflow/python/keras/engine/training.py:747 train_step
y_pred = self(x,training=True)
/usr/local/lib/python3.6/dist-packages/tensorflow/python/keras/engine/base_layer.py:976 __call__
self.name)
/usr/local/lib/python3.6/dist-packages/tensorflow/python/keras/engine/input_spec.py:216 assert_input_compatibility
' but received input with shape ' + str(shape))
ValueError: Input 0 of layer sequential_10 is incompatible with the layer: expected axis -1 of input shape to have value 1 but received input with shape [32,2]
解决方法
要解决您的问题,您应该做三件事:
1-像这样将dtype
中的multiplication_q
从object
更改为int
:
multiplication_q = np.array([[10,10],[1,1],[2,2],[0,0],[3,3],[4,4],[5,5],[6,6],[7,7],[8,8],[9,9],[11,[27,[30,[17,22],[20,13],[21,[19,24],19],11],15],12],[15,[18,[49,[12,4]],dtype=int)
2-在模型的第一个密集层中,使用input_shape=(2,)
代替input_shape=[1]
,如下所示:
model = tf.keras.Sequential([
tf.keras.layers.Dense(units=4,input_shape=(2,)),tf.keras.layers.Dense(units=4),tf.keras.layers.Dense(units=1)
])
3-对于预测函数,您应该传递list
的{{1}}而不是list
,因为您使用{{1}的list
进行了训练}
list
,
尝试将第一密集层中的输入设置为multiplication_q.shape
,将输入形状设置为1
时将输入形状设置为32,2
编辑:下面的代码解决了您的问题,尽管由于它不是很准确,所以您必须尝试一些东西。
import tensorflow as tf
import numpy as np
import matplotlib.pyplot as plt
multiplication_q = np.asarray([[10,4]])
multiplication_a = np.asarray([100,1,4,9,16,25,36,49,64,96,110,60,12,374,104,84,456,209,20,121,15,24,45,343,35,48])
multiplication_q = multiplication_q/np.amax(multiplication_q)
multiplication_a = multiplication_a/np.amax(multiplication_a)
model = tf.keras.models.Sequential()
model.add(tf.keras.Input(shape=(2,)))
model.add(tf.keras.layers.Dense(32,activation='relu'))
model.add(tf.keras.layers.Dense(units=1))
model.compile(loss='mean_squared_error',optimizer=tf.keras.optimizers.Adam(0.1))
history = model.fit(multiplication_q,multiplication_a,epochs=750)
print(model.predict(np.asarray([[4,5]])/np.amax(multiplication_q)*np.amax(multiplication_a)))