问题描述
我有什么
经理和模型
有了经理,我可以得到那些已实现,人为制造或已规定的案件。
from datetime import date
class CaseManager(models.Manager):
"""Define a manager for Case model."""
def fulfilled(self):
"""Get all cases that will fulfill soon."""
return self.get_queryset().filter(fulfillment=date.today())
def caducated(self):
"""Get all cases that will caducate soon."""
return self.get_queryset().filter(caducity=date.today())
def prescribed(self):
"""Get all cases that will prescribe soon."""
return self.get_queryset().filter(prescription=date.today())
class Case(models.Model):
"""Representation of a legal case."""
fulfillment = models.DateField(verbose_name=_("Fulfillment"),default=date.today)
caducity = models.DateField(verbose_name=_("Caducity"),default=date.today)
prescription = models.DateField(verbose_name=_("Prescription"),default=date.today)
objects = CaseManager()
工厂
创建假案进行测试。
class CaseFactory(DjangoModelFactory):
"""Define Case Factory"""
fulfillment = Faker("date")
caducity = Faker("date")
prescription = Faker("date")
class Meta:
model = Case
我尝试过的事情
测试
class TestCasesManagers:
def test_fulfilled(self):
case = CaseFactory(fulfillment=date.today())
assert case in Case.objects.fulfilled()
def test_caducated(self):
case = CaseFactory(caducity=date.today())
assert case in Case.objects.caducated()
def test_prescribed(self):
case = CaseFactory(prescription=date.today())
assert case in Case.objects.prescribed()
问题
使用这种方法,我必须对管理器中所有相似且不可扩展的方法重复几乎相同的测试。
我想要什么
解决方法
您可以使用对象列表来概括这些内容:
class TestCasesManagers:
kws = [
('fulfillment','fulfilled'),('caducity','caducated'),('prescription','prescribed')
]
def make_test(ky,mg):
def f(self):
case = CaseFactory(**{ky: date.today()})
assert case in getattr(Case.objects,mg)()
return f
for ky,mg in kws:
locals()[f'test_{mg}'] = make_test(ky,mg)
del make_test
因此,您可以轻松地向列表kws
添加一个额外的2元组来测试此组合。这些仍然是单个测试,因此您可以决定仅运行管理器功能中的一个测试,或仅重试失败的功能。