DIDISOFT PGP Lib在解密特定字符串期间挂起

编程问答 2022-08-14

问题描述

当我加密下面的字符串时，下面的字符串的长度显然大于1024，并且一旦加密就可以解密，但是一旦字符串减少到小于1024，就可以解密而不会挂起

String s = "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?>\n"
                + "<FTSingleCreditResponse>\n"
                + "    <Amount>1000.00</Amount>\n"
                + "    <BeneficiaryAccountName>Akogun Olasoji</BeneficiaryAccountName>\n"
                + "    <BeneficiaryAccountNumber>000000020</BeneficiaryAccountNumber>\n"
                + "    <BeneficiaryBankVerificationNumber></BeneficiaryBankVerificationNumber>\n"
                + "    <BeneficiaryKYCLevel>1</BeneficiaryKYCLevel>\n"
                + "    <ChannelCode>12</ChannelCode>\n"
                + "    <DestinationInstitutionCode>999194</DestinationInstitutionCode>\n"
                + "    <NameEnquiryRef>999999200825144654200825144654</NameEnquiryRef>\n"
                + "    <Narration>Transaction from me you</Narration>\n"
                + "    <OriginatorAccountName>Ajao Niyi</OriginatorAccountName>\n"
                + "    <OriginatorAccountNumber>0105498919</OriginatorAccountNumber>\n"
                + "    <OriginatorBankVerificationNumber>10000000002</OriginatorBankVerificationNumber>\n"
                + "    <OriginatorKYCLevel>1</OriginatorKYCLevel>\n"
                + "    <PaymentReference>ref/2015/08/05/val 3</PaymentReference>\n"
                + "    <ResponseCode>00</ResponseCode>\n"
                + "    <SessionID>999999200827170808200827170807</SessionID>\n"
                + "    <TransactionLocation>6.4300747,3.4110715</TransactionLocation>\n"
                + "</FTSingleCreditResponse>";

PGPLib在解密上述字符串的加密结果时会动手。

下面是我使用pgpLib进行的加密和解密方法

加密 

public String encrypt(String text) {
        try {
            PGPLib pgp = new PGPLib();
            boolean armor = false;
            boolean withIntegrityCheck = true;

            ByteArrayOutputStream o = new ByteArrayOutputStream();
            logger.debug("step 1");
            InputStream is = new ByteArrayInputStream(text.getBytes("UTF-8"));
            logger.debug("step 2");
            if (publicKeyFile == null) {
                publicKeyFile = new File(publicKeyLocation);
            }
            logger.debug("step 3");
            InputStream publicKeyStream = new FileInputStream(publicKeyFile);
            logger.debug("step 4");
            pgp.encryptStream(is,publicKeyLocation,publicKeyStream,o,armor,withIntegrityCheck);
            logger.debug("step 5");
            byte[] body = o.toByteArray();
            int numberRead = body.length;
            logger.debug(" -|- SSModuleClient :: pickMessage :: numberRead: " + numberRead);
            return byte2hex(body);
        } catch (IOException ex) {
            logger.debug(" -|- SSModule :: MessageProcessor :: encrypt () :: Error Occurred ..."
                    + ex.getMessage());
            logger.debug("SSModule",ex);
        } catch (PGPException ex) {
            logger.debug(" -|- SSModule :: MessageProcessor :: encrypt () :: Error Occurred ..."
                    + ex.getMessage());
            logger.debug("SSModule",ex);
        }

        return "";
    }

解密 

public String decrypt(String text) {

        String decryptedMessage = "";

        try {
            byte[] bytText = hex2byte(text);

            PGPLib pgp = new PGPLib();

            InputStream iStream = new ByteArrayInputStream(bytText);

            logger.debug("SSModule :: decrypt () :: iStream.available(): "
                    + iStream.available());

            if (privateKeyFile == null) {
                privateKeyFile = new File(privateKeyLocation);
            }
            InputStream privateKeyStream = new FileInputStream(privateKeyLocation);
            PipedInputStream pin = new PipedInputStream();
            OutputStream oStream = new PipedOutputStream(pin);

            logger.debug("text: " + text);

            logger.info("privateKeyPassphrase: " + privateKeyPassphrase);

            pgp.decryptStream(iStream,privateKeyStream,getPrivateKeyPassphrase(),oStream);
            do {
                logger.debug("pin.available(): " + pin.available());
            } while (pin.available() <= 0);
            byte[] body = new byte[pin.available()];
            pin.read(body);
            decryptedMessage = new String(body).toString();
        } catch (Exception ex) {
            logger.debug("SSModule :: MessageProcessor :: decrypt () :: Error Occurred ..."
                    + ex.getMessage());
            logger.debug("SSModule",ex);
        }

        return decryptedMessage;
    }

从解密方法来看，它不会超出pgp.decryptStream，它只是挂起并且不会走得更远，其他字符串可以很好地加密和解密，但是这个特定字符串不能做到

解决方法

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encryptionjavajavapgp