基于输入的Python Discount函数

问题描述

我正在尝试创建一个Python程序，根据购买的数量（您将这些书称为“书1”，“书2”等，并保存在列表中）来计算您在书上获得的折扣。该程序应接受您的输入（例如：第1本书，第2本书） 如果同一本书被购买两次，则没有折扣，但是，如果购买了两本或更多本不同的书籍，则五本书中的任何一本书的单本售价为8欧元

• 如果购买了该系列的两本不同的书籍，则可享受5％的折扣
• 如果购买了该系列的三本不同的书籍，则可享受10％的折扣
• 如果购买了该系列的四本不同的书籍，则可享受20％的折扣
• 如果购买了该系列的全部五本书，将享受25％的折扣
• 如果客户购买了一本书的两本书，则第二本书的价格为8欧元，除非有更多重复的另一本书可以作为第二本书的一部分应用折扣，否则第二本书将没有任何折扣。

我的代码在下面，由于遇到很多语法错误，我不确定我哪里出错了，而且我认为我没有所有需要的信息。

#list of books
books = ["book 1","book 2","book 3","book 4","book 5"]
if books <= 1
    print("One book is 8 EURO - no discount")
elif books <= 2
    books discount =books*0.05
elif books <= 3
    books discount =books*0.10
elif books <= 4
    books discount =books*0.20
elif books <= 5
    books discount =books*0.25

print("Discount : ",discount)
print("Total cost  : ",price -discount)

else:
print("no discount if two books of the same title are purchased")

解决方法

我会做这样的事情：

{{1}}

当心，未经测试，您必须找到错误，但我希望它会在可行的解决方案过程中为您设置

,

尝试一下

books =["book 1","book 2","book 3","book 4","book 5"]
price = 8

nos = len(books)
purchase = []
tDiscount = 0
tPrice = 0

for i in range(1,nos+1):
    print("Enter quantity of book ",i,": ")
    num = int(input())
    if num == 0:
        tDiscount += 0
        print(" Price: 0\n Discount: 0\n")
    elif num == 1:
        print(" One book is 8 EURO - no discount\n Price: ",price,"\n")
        tPrice += price
    elif num == 2:
        tDiscount += price * 0.05
        print(" Price: ",num * price,"\n Discount : ",price * 0.05,"\n")
        tPrice += (num * price)
    elif num == 3:
        tDiscount += price * 0.10
        print(" Price: ",price * 0.10,"\n")
        tPrice += (num * price)
    elif num == 4:
        tDiscount += price * 0.20
        print(" Price: ",price * 0.20,"\n")
        tPrice += num * price
    else:
        tDiscount += price * 0.25
        print(" Price: ",price * 0.25,"\n")
        tPrice += (num * price)

print("\nBill: ",tPrice,"\nDiscount: ",tDiscount,"\nTotal Bill: ",tPrice - tDiscount)

希望对您有所帮助