将数组合并为一个数组

问题描述

让我说我有以下数组，如何通过修改给定的reduce函数来实现此问题中的最后一个给定示例？

我试图将[cur]分配给一个计划密钥，但是它只将第一个元素放出。

我觉得这与我连接对象的方式有关，但是我无法自行解决。

{
   employee: 'employee_1',customer: {
     name: 'customer_1',},startdate: '2020-03-01T23:00:00.000Z'
},{
   employee: 'employee_2',{
   employee: 'employee_3',startdate: '2020-03-01T23:00:00.000Z'
}

plans.reduce(function(o,cur) {

   // Get the index of the key-value pair.
   var occurs = o.reduce(function(n,item,i) {
      return (item.customer.toString() === cur.customer.toString()) ? i : n;
   },-1);

   // If the name is found,if (occurs >= 0) {
      // append the current value to its list of values.
      o[occurs].employee = o[occurs].employee.concat(cur.employee)
      o[occurs].startdate = o[occurs].startdate.concat(cur.startdate)

   // Otherwise
   } else {

      // add the current item to o (but make sure the value is an array).
      var obj = {
         customer: cur.customer,employee: [cur.employee],startdate: [cur.startdate]
      };
      o = o.concat([obj]);
   }
   return o;
},[])

这会将给定的数组简化为如下形式：

{
   customer: {
     name: 'customer_1'
   },employee: [{
     employee: 'employee_1'
   },{
     employee: 'employee_2'
   },{
     employee: 'employee_3'
   }],startdate: [{
     startdate: '2020-03-01T23:00:00.000Z'
   },{
     startdate: '2020-03-01T23:00:00.000Z'
   },{
     startdate: '2020-03-01T23:00:00.000Z'
   }]  
}

但是我需要的是这样的

{
   customer: {customer_data},plans: [{
     employee: 'employee_1',startdate: '2020-03-01T23:00:00.000Z' 
   },{
     employee: 'employee_2',{
     employee: 'employee_3',startdate: '2020-03-01T23:00:00.000Z' 
   }]
}

解决方法

我修改了您的解决方案，以获得所需的输出。

您应该使用find方法来检查客户是否已存在于数组中，而不是使用reduce方法。 另外，您没有考虑plans数组，我已经添加了。

var plans = [
{
   employee: 'employee_1',customer: {
     name: 'customer_1',},startdate: '2020-03-01T23:00:00.000Z'
},{
   employee: 'employee_2',{
   employee: 'employee_3',startdate: '2020-03-01T23:00:00.000Z'
}
];


var result = plans.reduce(function(o,cur) {

   // Get the index of the key-value pair.
   var occurs = o.find(ob=> ob.customer.name === cur.customer.name);

   // If the name is found,if (occurs) {
      // append the current value to its list of values.
      occurs.plans.push( {employee: cur.employee,startdate: cur.startdate}  )
   // Otherwise
   } else {

      // add the current item to o (but make sure the value is an array).
      var obj = {
         customer: cur.customer,plans:[
          {employee: cur.employee,startdate: cur.startdate}
         ]
      };
      o = o.concat(obj);
   }
   return o;
},[])

console.log(result)