问题描述
我正在尝试使用月份的英语序数后缀生成日期范围from 1 to 28
。例如:1st of month
,2nd of month
...
for($i = 1; $i <= 28; $i++)
{
$arrayRange[] = date('dS',strtotime($i));
}
echo "<pre>";
print_r($arrayRange);
echo "</pre>";
输出:
Array
(
[0] => 01st
[1] => 01st
[2] => 01st
...
[26] => 01st
[27] => 01st
)
我在做什么错..?
解决方法
您应将正确的时间戳记作为日期函数的第二个参数,并使用j
(无前导零)日期格式:
list($m,$y) = explode('-',date('m-Y'));
for($d = 1; $d <= 28; $d++)
{
$arrayRange[] = date('jS',mktime(0,$m,$d,$y));
}
echo "<pre>";
print_r($arrayRange);
echo "</pre>";
,
尝试此操作,它使用“ +1天”等上下文日期功能将您的整数注册为一天:)
要回答第二个问题-正如您做错了什么-您要将整数传递给function that expects a string。
<?php
for($i = 0; $i <= 27; $i++)
{
//The February is there to keep '1st' a '1st' even on days when it's not
//the '31st'
$arrayRange[] = date('dS',strtotime("1st february +".$i.' day'));
}
echo "<pre>";
print_r($arrayRange);
echo "</pre>";
输出:
Array
(
[0] => 01st
[1] => 02nd
...
[28] => 28th
)¨
编辑:
要删除0,可以这样使用ltrim():
$arrayRange[$i] = ltrim(date('dS',strtotime("1st february +".$i.' day')),"0");
哪个会给你这样的输出
[0] => 1st
[1] => 2nd
...
[28] => 28th
编辑2: 解决它。提醒MLF的错误提示。
,您可以使用类似这样的内容:
$arrayRange[] = (new DateTime('Aug '.$i))->format('jS');