Android Studio中的位置弹出菜单

问题描述

我的应用程序的右上角有我的按钮(btnlogout)。当我按下它时,我希望弹出菜单从右上角显示。现在,它在屏幕中间弹出。我发现了类似的问题,但是我无法正确使用重力。

这是我的代码


 btnlogout.setonClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {


                PopupMenu popupMenu = new PopupMenu(MainActivity.this,button,Gravity.LEFT);
                popupMenu.getMenuInflater().inflate(R.menu.popup_menu,popupMenu.getMenu());


                popupMenu.setonMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {
                    @Override
                    public boolean onMenuItemClick(MenuItem menuItem) {



                        int id = menuItem.getItemId();

                        if (id == R.id.loggout) {
                            Intent myintent = new Intent(MainActivity.this,Innlogg.class);
                            startActivity(myintent);
                            return false;
                        }

                        if (id == R.id.privacy) {
                            Intent myWebLink = new Intent(android.content.Intent.ACTION_VIEW);
                            myWebLink.setData(Uri.parse("https://www.bi.edu/about-bi/privacy-policy-and-cookies"));
                            startActivity(myWebLink);

                        }

                            return true;
                    }
                });
                popupMenu.show();
            }
        }); ``` 

解决方法

//allows you to set PopupMenu to the specified coordinates
private void show(Activity pActivity,float x,float y)
        {
             final ViewGroup root = (ViewGroup) 
             pActivity.getWindow().getDecorView().findViewById(android.R.id.content);
             final View view = new View(context);
             view.setLayoutParams(new ViewGroup.LayoutParams(1,1));
             view.setBackgroundColor(Color.TRANSPARENT);
             root.addView(view);
             view.setX(x);
             view.setY(y);
             PopupMenu menu = new PopupMenu(context,view,Gravity.CENTER);
             menu.setOnDismissListener(new PopupMenu.OnDismissListener()
                 {
                      @Override
                      public void onDismiss(PopupMenu menu)
                      {
                            root.removeView(view);
                       }
                 });
            menu.show();
        }

相关问答

Selenium Web驱动程序和Java。元素在(x,y)点处不可单击。其...
Python-如何使用点“。” 访问字典成员?
Java 字符串是不可变的。到底是什么意思?
Java中的“ final”关键字如何工作?(我仍然可以修改对象。...
“loop:”在Java代码中。这是什么,为什么要编译?
java.lang.ClassNotFoundException:sun.jdbc.odbc.JdbcOdbc...