问题描述
当我尝试调用.decode()解码结构时,它返回nil。有人可以帮助我吗?
我的应用从这行代码的JSON数据中返回空值:
let newPosData = try JSONDecoder().decode(NewPosDataBase.self,from: responseData)
以下是完整的代码:
func getNewLFNREXT(invnr: String,completionHandler: @escaping (String,Bool,NewPosDataBase?) -> Void) {
let headers: HTTPHeaders = [
.authorization(username: UserCredentials.shared.username,password: UserCredentials.shared.password),.accept("application/json")
]
let url:String = Config.middleware + Config.url + "/mobile/lfnrext?invnr=\(invnr)"
AF.request(url,method: .get,parameters: [:],headers: headers).responseJSON { response in
if response.response?.statusCode == 200 {
do {
guard let responseData = response.data else {
completionHandler(errorMessage,false,nil )
return
}
let newPosData = try JSONDecoder().decode(NewPosDataBase.self,from: responseData)
print( newPosData.newPosData?.newLfnrext)
completionHandler("",true,newPosData)
} catch {
completionHandler(errorMessage,nil )
}
}else {
let message = self.getErrorMessageFrom(data: response.data,defaultErrorMessage: errorKeineDaten)
completionHandler(message,nil)
}
}
}
解决方法
如果键名不同于enum CodingKeys
类型的属性名,则需要添加 Codable
。
因此,您的模型应该像
class NewPosDataBase: Codable {
enum CodingKeys: String,CodingKey {
case newPosData = "NEW_POS_DATA"
}
//rest of the code...
}
class NewPosData: Codable {
enum CodingKeys: String,CodingKey {
case newLfnrext = "NEW_LFNREXT"
case aktuellerZahler = "AKTUELLER_ZAHLER"
case gpsStd = "GPS_STD"
}
//rest of the code...
}
注意:除非您出于特定目的需要它们,否则无需在模型中提供任何init
实现。