如何在电视节目中留下具有ID的频道或组?

问题描述

您好,我正在尝试使用此脚本保留一个ID为ID的频道,但它不能很好地显示任何结果LeaveChannelRequest对我也不起作用 这是我尝试过的:

import asyncio
import logging
import re
import time
import os
import sys
import requests

logging.basicConfig(level=logging.ERROR)

from telethon import TelegramClient,events
from telethon.tl.functions.channels import LeaveChannelRequest
from telethon.tl.functions.channels import JoinChannelRequest
from telethon.tl.functions.messages import GetBotCallbackAnswerRequest
from datetime import datetime
from colorama import Fore,init as color_ama
color_ama(autoreset=True)

os.system('cls' if os.name=='nt' else 'clear')

# my.telegram.org values,get your own there
api_id = ''
api_hash = ''

input_channel = '-1001226909513'
def print_msg_time(message):
    print('[' + Fore.YELLOW + f'{datetime.Now().strftime("%H:%M:%s")}' + Fore.RESET + f'] {message}')
async def main():
    if len(sys.argv) < 2:
        print('Usage: python start.py phone_number')
        print('-> Input number in international format (example: +10123456789)\n')
        e = input('Press any key to exit...')
        exit(1)

    phone_number = sys.argv[1]

    if not os.path.exists("session"):
        os.mkdir("session")
    client = TelegramClient('session/' + phone_number,api_id,api_hash)
    await client.start(phone_number)
    me = await client.get_me()
    print(Fore.GREEN + f'               Current account: {me.first_name}({me.username})\n' + Fore.RESET)
    print_msg_time('leaving channels')
    async def main():
        await client.delete_dialog(input_channel)
        print_msg_time(f'{input_channel} has been leaved')

asyncio.get_event_loop().run_until_complete(main())

我的问题在哪里?

解决方法

离开通道或组的方法调用是在内部函数中定义的

[...]
print_msg_time('leaving channels')
async def main():
    await client.delete_dialog(input_channel)
    print_msg_time(f'{input_channel} has been leaved')

在外部函数中没有被调用,您可以避免使用内部函数。例如,您可以像这样调用delete_dialog方法

[...]
print_msg_time('leaving channels')
await client.delete_dialog(input_channel)
print_msg_time(f'{input_channel} has been leaved')