问题描述
我已经完成了一项任务,并且一直试图解决这个问题已经无济于事了。纸质记录可以嵌套在字典的任何级别
children
到目前为止,我只能从代码中获得键和值对,但是我去了任何地方。任何人都可以留下想法
sales highest_sales
sales.yml/sales1/paper1 Dwight
{'sales1': {'paper1': {'Jim': 8,'Pam': 9,'Dwight': 43}},'sales2': {'morning_sales': {'paper2': {'Jim': 10,'Pam': 23,'Dwight': 67,'Michael': 12}},'evening_sales': {'paper3': {'Jim': 3,'Pam': 43,'Dwight': 67}}},'paper4': {'Jim': 23,'Pam': 14,'Dwight': 8}}
解决方法
可以使用operator.itemgetter
Documentation找到最大值的键
您可以尝试使用此代码,它应该可以工作
import yaml
import operator
def check_max(k,v,prev_key):
try:
# To get key of maximum sale
sales = max(v.items(),key=operator.itemgetter(1))[0]
if 'sales' in sales or 'paper' in sales:
# To check if value is another dictionary
raise Exception("value is a dictionary")
print("{:38s} {:10s}".format(str(prev_key)+'/'+str(k),sales))
except:
# The value was a dictionary
for k1,v1 in v.items():
check_max(k1,v1,prev_key+'/'+str(k))
with open(r"C:\Users\Jason\Assignments\Assignment8\sales.yml",'r') as yamlfile:
data = yaml.load(yamlfile,Loader=yaml.FullLoader)
# Formatting of data you can
# increase the value for proper formatting
print("{:38s} {:10s}".format("sales","highest_sales"))
for k,v in data.items():
check_max(k,'sales.yml')
输出:
sales highest_sales
sales.yml/sales1/paper1 Dwight
sales.yml/sales2/morning_sales/paper2 Dwight
sales.yml/sales2/evening_sales/paper3 Dwight
sales.yml/paper4 Jim