在CakePHP中,如何从图像数组中获取客户端文件名?

问题描述

我正在尝试将图像上传到数组中。我希望数组存储图像的名称。但是,每次使用getClientFilename()方法获取图像名称时,都会出现错误。我得到的错误是:

在数组上调用成员函数getClientFilename()

,并且此错误是因为$otherName变量使用getClientFilename()方法。如何从一组图像中获取客户端文件名?如果您查看图片示例,我想获取vashion.jpg的clientfilename值。

SubmissionsController.PHP

if(!is_dir(WWW_ROOT.'otherImg'.DS.$folder)) {
    mkdir(WWW_ROOT.'otherImg'.DS.$folder,0775);
}
foreach($this->request->getData('data') as $otherImage) {
    debug($otherImage);
    $otherName = $otherImage->getClientFilename();
    //Add to data to save
    $imgData = array(
        "original_pathname" => $otherImage,"submission_id" => $submission->id
    );

    $this->Submission->Image->create();
    $this->Submission->Image->save($imgData);
                    
    if(!$this->Submission->Image->save($imgData)) {
        $this->Flash->error(__('The other images Could not be uploaded.'));
    }
}

add.PHP

<table id="uploads_table">
    <thead>
        <tr>
            <th colspan="2">Upload Other Images (max of 25)<input type="hidden" name="data[Image][num_images]" id="num_images" value="1" /></th>
        </tr>
    </thead>
    <tfoot></tfoot>
    <tbody>
        <tr>
            <td><input type="file" name="data[Image][file][]" id="ImageFile1" /></td>
            <td><input type="button" id="add_image" name="add_image" value="Add Another Image" /></td>
        </tr>
    </tbody>
</table>

此图显示了foreach循环的调试输出。我正在尝试返回clientfilename。

enter image description here

解决方法

我可以使用以下代码找到解决问题的方法:

foreach($this->request->getData('data') as $otherImage) {
  for($key = 0; $key < $otherImage['num_images']; $key++) {
     $otherName = $otherImage['file'][$key]->getClientFilename(); //Get file original name
     //Add to data to save
     $imgData = array(
        "original_pathname" => $folder.'/'.$otherName,"submission_id" => $submission->id
      );

      if($otherName) {
       $otherImage['file'][$key]->moveTo(WWW_ROOT.'otherImg'.DS.$folder.DS.$otherName); // move files to destination folder
      }
   }
}

这将返回vashion.jpg