将项目提取到R tibble中的特定位置

问题描述

def __init__(self,*args,**kwargs):
    self.user = kwargs.pop('user',None)
    super(ContactResource,self).__init__(*args,**kwargs)

company = fields.Field(column_name='company')

class Meta:
    model = Contact
    skip_unchanged = True
    report_skipped = True
    exclude =('is_active','created_by')
    export_order = ('id','first_name','last_name','email','phone','address','description','company','created_on','website','job_title','birthday')

def after_import_instance(self,instance,new,**kwargs):
    instance.created_by = self.user # kwargs['user']

def import_field(self,field,obj,data):
    field_name = self.get_field_name(field)
    method = getattr(self,'clean_%s' % field_name,None)
    if method is not None:
        obj = method(field,data)
    super(ContactResource,self).import_field(field,data)

def clean_company(self,data):
    name = data[field.column_name]
    company,created = Company.objects.get_or_create(name=name,created_by=self.user)
    obj.company = company
    return obj

如何提取library(tibble) x <- tibble(c('a','b','c'))的值？如果我设置x[1,]，它会给我一个1x1的小滴。我不要那个。我只想要值“ a”。

解决方法

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r r tibble