问题描述
我有下表
CREATE TABLE employee(id serial PRIMARY KEY,employee jsonb);
CREATE TABLE perks_details(id serial PRIMARY KEY,details jsonb);
insert into employee(employee) values
('{"name": "name1","perks": [
{"id": 123,"valid_from": "T23:28:56.782Z"},{"id": 456,{"id": 789,"valid_from": "T23:28:56.782Z"}
]
}');
insert into perks_details(details) values('{"id":123,"detail1":"lorem","detail2":"lorem"}');
insert into perks_details(details) values('{"id":123,"detail3":"lorem","detail4":"lorem"}');
insert into perks_details(details) values('{"id":456,"detail5":"lorem","detail6":"lorem"}');
如何在perks_details表和聚合函数中,以employee
左连接perks_details
的特权ID和ID编写选择查询,以便我的结果数据如下:
{
"name": "name1","perks": [
{
"id": 123,"valid_from": "T23:28:56.782Z","details": [
{
"id": 123,"detail1": "lorem","detail2": "lorem"
},{
"id": 123,"detail3": "lorem","detail4": "lorem"
}
]
},{
"id": 456,"details": [
{
"id": 456,"detail5": "lorem","detail6": "lorem"
}
]
},{
"id": 789,"details": []
}
]
}
我尝试了多种变体,无法接近有效的查询。请在这里建议/协助我。
select e.id,perk,perks_details.details
from employee AS e,jsonb_array_elements(employee->'perks') perk
LEFT JOIN perks_details on perks_details.details -> 'id' = perk->'id'
group by e.id,perk.value,perks_details.details;
解决方法
嗨,您可以通过以下方式做到这一点:
with cte as (
select t1.employee->>'name' "name",t2.id,t2.valid_from,json_agg(t3.details) "details"
from employee t1
cross join lateral jsonb_to_recordset(employee->'perks') as t2(id int,valid_from time)
left join perks_details t3 on t2.id::text=t3.details->>'id'
group by 1,2,3
)
select row_to_json(t) from (
select
name,json_agg(jsonb_build_object('id',id,'valid_from',valid_from,'details',details)) "perks"
from cte group by name
) t