问题描述
我刚刚开始使用Python进行编程,我尝试使用tkinter
创建一个GUI,在该GUI中,用户会要求用户选择一个zip文件和解压缩后的文件目标。我注意到的是,当用户重新输入目标位置时,它仍然还会存储先前的文件目录。我该如何预防?
import tkinter as tk
from tkinter import filedialog
# Setting the window size
screenHeight = 450
screenWidth = 350
root = tk.Tk()
# get the location of the zip file
def input_dir():
input_filedir = filedialog.askopenfilename(initialdir='/',title='Select File',filetypes=(("zip","*.zip"),("all files","*.*")))
my_label.pack()
return input_filedir
# get location of destination for file
def output_dir():
output_filename = filedialog.askdirectory()
# Setting the canvas size to insert our frames
canvas = tk.Canvas(root,height=screenHeight,width=screenWidth)
canvas.pack()
# Setting the frame size to insert all our widgets
frame = tk.Frame(root,bg='#002060')
frame.place(relwidth=1,relheight=1)
# button to get user to chose file directory
openFile = tk.Button(frame,text='Choose the file path you want to extract',command=input_dir)
openFile.pack(side='top')
# button to get destination path
saveFile = tk.Button(frame,text="Chose the location to save the file",command=output_dir)
saveFile.pack(side='bottom')
extractButton = tk.Button(frame,text="Extract Now")
root.mainloop()
我尝试在def input_dir
函数中添加此行代码,但它更改了按钮的位置。我仍在研究提取zip的代码。
for widget in frame.winfor_children():
if isinstance(widget,tk.Label):
widget.destroy()
解决方法
用户单击的文件/目录并未真正保存。当变量各自的功能完成时,它们的input_filedir和output_filename将被垃圾回收。如果您谈论的是对话框如何返回到对话框中打开的最新位置,那确实不是一件容易的事。简单的答案是,在创建对话框时,您可以添加关键字“ initialdir”,就像这样:
output_filename = filedialog.askdirectory(initialdir='C:/This/sort/of/thing/')
长的答案是filedialog.ask目录实际上创建了一个filedialog.Directory实例,并且在该类中,它将信息保存在以后称为_fixresult的方法中(但是该方法还可以做其他重要的事情。)您可以通过执行以下操作来覆盖此内容:
class MyDirectory(filedialog.Directory):
def _fixresult(self,widget,result):
"""
this is just a copy of filedialog.Directory._fixresult without
the part that saves the directory for next time
"""
if result:
# convert Tcl path objects to strings
try:
result = result.string
except AttributeError:
# it already is a string
pass
self.directory = result # compatibility
return result
def askdirectory (**options):
"Ask for a directory,and return the file name"
return MyDirectory(**options).show()
,然后使用您自己的askdirectory函数而不是filedialog.ask目录,但这确实很复杂,因此,我建议如果可以的话,改用initialdir。
P.S。单击按钮时,它会在您创建按钮时调用您在“ command =”之后设置的功能;看来你明白了。但是这些函数是“ void”的,因为它们的返回仅被忽略。也就是说,“ return input_filedir”行没有任何作用。