如何根据另一个阵列的条件用于一副扑克牌从一个阵列中排除一项？

问题描述

我有两个数组，一个用于卡片套装suit_list = ["Hearts","Diamonds","Clubs","Spades"]，另一个用于值value_list = ["A","2","3","4","5","6","7","8","9","10","J","Q","K"]

我已经编写了用于随机选择卡的代码。

基于此，对于选定的随机卡，例如2颗钻石，我想防止再次被选中。

我该如何解决这种方法？我最初的想法是在嵌套的for循环中使用条件方法，但似乎不起作用。

感谢您的帮助。

解决方法

与其考虑从游戏中移除一张牌，为什么不创建牌组，将其洗牌，然后当您需要牌组中的牌时，只需从阵列中取出下一张牌即可。

import random
import itertools

suit_list = ["Hearts","Diamonds","Clubs","Spades"]
value_list = ["A","2","3","4","5","6","7","8","9","10","J","Q","K"]

deck = list(itertools.product(suit_list,value_list))
random.shuffle(deck)

for card in deck:
    print(card)