如何使用异议JS一对一地联接表

问题描述

我刚刚使用了knex异议js。目前，我与一对多表的关系如下。

表user_groups：

   Column   |           Type           | Collation | Nullable |                  Default                   | Storage  | Stats target | Description 
------------+--------------------------+-----------+----------+--------------------------------------------+----------+--------------+-------------
 id         | integer                  |           | not null | nextval('dl_user_groups_id_seq'::regclass) | plain    |              | 
 title      | character varying(128)   |           | not null |                                            | extended |              | 
 slug       | character varying(128)   |           | not null |                                            | extended |              | 
 desc       | character varying(512)   |           |          |                                            | extended |              | 
 created_at | timestamp with time zone |           | not null | CURRENT_TIMESTAMP                          | plain    |              | 
 updated_at | timestamp with time zone |           | not null | CURRENT_TIMESTAMP                          | plain    |              | 

表角色：

    Column     |           Type           | Collation | Nullable |               Default                | Storage  | Stats target | Description 
---------------+--------------------------+-----------+----------+--------------------------------------+----------+--------------+-------------
 id            | integer                  |           | not null | nextval('dl_roles_id_seq'::regclass) | plain    |              | 
 user_group_id | integer                  |           | not null |                                      | plain    |              | 
 title         | character varying(128)   |           | not null |                                      | extended |              | 
 slug          | character varying(128)   |           | not null |                                      | extended |              | 
 desc          | character varying(512)   |           |          |                                      | extended |              | 
 created_at    | timestamp with time zone |           | not null | CURRENT_TIMESTAMP                    | plain    |              | 
 updated_at    | timestamp with time zone |           | not null | CURRENT_TIMESTAMP                    | plain    |              | 

这可以为role.js建模：

'use strict';

const { Model } = require('objection');
const UserGroupsModel = require(__basedir + '/app/models/user_groups');


class RolesModel extends Model {
    static get tableName() {
        return 'dl_roles';
    }

    static get jsonSchema() {
        return {
            type: 'object',required: ['user_group_id','title'],properties: {
                id: { type: 'integer' },user_group_id: { type: 'integer' },title: { type: 'string',minLength: 1,maxLength: 128 },slug: { type: 'string',desc: { type: 'string',maxLenght: 512 }
            }
        }
    }

    static get relationMappings() {
        return {
            user_groups: {
                relation: Model.BelongsToOneRelation,modelClass: UserGroupsModel,join: {
                    from: 'dl_roles.user_group_id',to: 'dl_user_groups.id'
                }
            }
        };
    };
}

module.exports = RolesModel;

user_groups.js

'use strict';

const { Model } = require('objection');
const Crypto = require('crypto');
const RolesModel = require(__basedir + '/app/models/roles');


class UserGroupsModel extends Model {
    static get tableName() {
        return 'dl_user_groups';
    }

    static get jsonSchema() {
        return {
            type: 'object',required: ['title'],maxLength: 512 }
            }
        }
    }

    static get relationMappings() {
        return {
            roles: {
                relation: Model.HasManyRelation,modelClass: RolesModel,join: {
                    from: 'dl_user_groups.id',to: 'dl_roles.user_group_id'
                }
            }
        };
    };
}

module.exports = UserGroupsModel;

这是我想转换为异议js的查询。

select ug.title as group,r.title as role,r.slug,r.desc 
from public.dl_roles r 
join public.dl_user_groups ug on r.user_group_id = ug.id;

结果：

 group  |     role      |     slug      | desc 
--------+---------------+---------------+------
 TELKM  | Administrator | administrator | 
 TELKM  | Instructor    | instructor    | 
 TELKM  | Learner       | learner       | 
 TELKM  | Guest         | guest         | 
 APPS   | Apps          | Apps          | 

这是我的异议查询：

'use strict';

const RolesModel = require(__basedir + '/app/models/roles');
const Slugify = require('slugify');


exports.getRolesAll = async function() {
    return new Promise(async (resolve,reject) => {
        try {
            let _data = await RolesModel
            .query()
            .joinRelated('user_groups');
            return resolve({
                statusCode: 200,data: _data,message: 'All data'
            });
        } catch (err) {
            return reject(err);
        }
    });
};

我尝试使用joinRelated和eager，但没有用。我希望Advanced可以给我答案，如何将一对多连接起来，并像上面的查询一样从父表中获取所有字段。

谢谢。

解决方法

我已经通过使用原始查询解决了我的问题。这是我的查询使用异议js。

RolesModel
.query()
.select('user_groups.*','roles.*')
.join('user_groups','user_groups.id','roles.user_group_id');

我希望这可以帮助某人。