UEFI c ++：使用“打印”时，发生wchar_t转换错误

问题描述

我想尝试在c ++中制作一些（U）EFI引导程序，但是，当我尝试使用g ++编译代码时，出现此错误：

boot.cpp: In function ‘EFI_STATUS efi_main(EFI_HANDLE,EFI_SYstem_TABLE*)’:
boot.cpp:9:9: error: invalid conversion from ‘const wchar_t*’ to ‘const CHAR16*’ {aka ‘const short unsigned int*’} [-fpermissive]
    9 |   Print(L"Hello,world!\n");
      |         ^~~~~~~~~~~~~~~~~~
      |         |
      |         const wchar_t*
In file included from boot.cpp:2:
/usr/include/efi/efilib.h:504:24: note:   initializing argument 1 of ‘UINTN Print(const CHAR16*,...)’
  504 |     IN CONST CHAR16   *fmt,

我使用了这个命令（我从Ubuntu WSL2开始工作）：

g++ boot.cpp -mno-red-zone -ffreestanding -fshort-wchar -nostdlib -e efi_main -Wl,-dll -shared -Wl,--subsystem,10 -c -I/usr/include/efi/ -I/usr/include/efi/x86_64/

这是我的代码：

#include <efi.h>
#include <efilib.h>

EFI_STATUS
EFIAPI
efi_main (EFI_HANDLE ImageHandle,EFI_SYstem_TABLE *SystemTable)
{
  InitializeLib(ImageHandle,SystemTable);
  Print(L"Hello,world!\n");
  return EFI_SUCCESS;
}

编辑： 如果我从“ Hello，world \ n”中删除L，则会出现此错误：

boot.cpp: In function ‘EFI_STATUS efi_main(EFI_HANDLE,EFI_SYstem_TABLE*)’:
boot.cpp:9:9: error: cannot convert ‘const char*’ to ‘const CHAR16*’ {aka ‘const short unsigned int*’}
    9 |   Print("Hello,world!\n");
      |         ^~~~~~~~~~~~~~~~~
      |         |
      |         const char*
In file included from boot.cpp:2:
/usr/include/efi/efilib.h:504:24: note:   initializing argument 1 of ‘UINTN Print(const CHAR16*,

编辑2： 如果我在hello world（u“ Hello，world \ n”）前面使用u，则会出现此错误：

boot.cpp: In function ‘EFI_STATUS efi_main(EFI_HANDLE,EFI_SYstem_TABLE*)’:
boot.cpp:9:9: error: invalid conversion from ‘const char16_t*’ to ‘const CHAR16*’ {aka ‘const short unsigned int*’} [-fpermissive]
    9 |   Print(u"Hello,world!\n");
      |         ^~~~~~~~~~~~~~~~~~
      |         |
      |         const char16_t*
In file included from boot.cpp:2:
/usr/include/efi/efilib.h:504:24: note:   initializing argument 1 of ‘UINTN Print(const CHAR16*,

解决方法

我确定，使用gcc代替g ++并转换为CHAR16 *