如何保持和运行程序始终形成最后一个值，因此当我再次打开程序时，程序将从最后一个值开始

问题描述

import random
 
amount = 100
loggedOn = True
 
while loggedOn:
    selection = int(input("Select 1 for Deposit,2 for Withdraw or 3 for Exit: "))
    if not selection:
        break
    if selection == 1:
        deposit = float(input("How much will you deposit? "))
        amount += deposit
        print(f"Deposit in the amount of ${format(deposit,'.2f')} ")
        print(f"Bank account balance ${format(amount,'.2f')} ")
    elif selection == 2:
        withdraw = float(input("How much will you withdraw? "))
        amount -= withdraw
        print(f"Withdraw in the amount of ${format(withdraw,'.2f')} ")
    else:
        loggedOn = False
 
print("Transaction number: ",random.randint(10000,1000000))

解决方法

编辑：泡菜解决方案 我看到你标记了这个泡菜。泡菜的解决方案几乎相同

#import the package
import pickle

#saving the variable
with open("last_amount.pickle",'wb') as f:
    pickle.dump(amount,f)

#getting the variable from save file
with open("last_amount.pickle",'rb') as f:
    amount = pickle.load(f)

您可以将金额保存在同一目录中的文件中。我假设在转义while循环时，程序在这里“关闭”。

此解决方案需要JSON

import json

节省最后一笔金额

with open("last_amount.txt",'w') as last_amount_file:
    last_amount_file.write(json.dumps(amount))
    #Place this in the block executed when the program closes.

现在，最后一笔金额被写入同一目录中名为“ last_amount”的文本文件中。要在再次打开程序时使用最后的金额，可以执行此操作。

使用上一个金额

with open("last_amount.txt",'r') as f:
    amount = json.loads(f.readline())

如果您有更多变量要保存和重复使用，则可能需要将文件命名为其他名称。

pickle python shelve