问题描述
我是使用Objective-C语言编程的新手。
我需要从函数for loop
中返回 this “ tabName”。如何比较app_additional_tab_name_
与tabName相等?因为现在仍然返回任何app_additional_tab_name_
的姓。
+ (Nsstring *)additionalTabName {
for (int i = 0; i <= 16; i++) {
tabNameConcatString = [NSMutableString stringWithFormat:@"app_additional_tab_name_%d",i];
tabName = [LocalizedStringsUserDefaults valueForKey:tabNameConcatString];
if ([LocalizedStringsUserDefaults existsObjectForKey:tabNameConcatString]) {
tabName = [LocalizedStringsUserDefaults valueForKey:tabNameConcatString];
NSLog(@"This tabName is: @% @% @% @%",tabName,@" and will append to: ",tabNameConcatString);
}
}
return tabName;
}
祝一切顺利。
解决方法
在匹配条件内移动返回
+ (NSString *)additionalTabName {
for (int i = 0; i <= 16; i++) {
tabNameConcatString = [NSMutableString stringWithFormat:@"app_additional_tab_name_%d",i];
tabName = [LocalizedStringsUserDefaults valueForKey:tabNameConcatString];
if ([LocalizedStringsUserDefaults existsObjectForKey:tabNameConcatString]) {
tabName = [LocalizedStringsUserDefaults valueForKey:tabNameConcatString];
NSLog(@"This tabName is: @% @% @% @%",tabName,@" and will append to: ",tabNameConcatString);
return tabName;
}
}
return nil;
}
如果未找到匹配项,则可以返回nil或返回空字符串。