通过使用蜂巢中的案例语句将额外的金额添加到薪水列

编程问答 2022-08-12

问题描述

下面的示例是出于我的学习目的。实际上，我尝试在emp表的“薪水”列中添加一些不同的金额，其中使用案例声明在每个部门中薪水最高的人

在下面的查询中，我检索了每个部门的最高工资

select * from (select rank() over (partition by job order by salary desc ) as rank,* from emp) as a where rank=1

a.rank  a.emp_no        a.ename a.job   a.mgr_id        a.date_of_joining       a.salary        a.bonus a.dept_no
1       7788    SCott   ANALYST 7566    09-DEC-1982     3000    NULL    20
1       7902    FORD    ANALYST 7566    3-DEC-1981      3000    NULL    20
1       7934    MILLER  CLERK   7782    23-JAN-1982     1300    NULL    10
1       7566    JOnes   MANAGER 7839    2-APR-1981      2975    NULL    20
1       7839    KING    PRESIDENT       NULL    17-NOV-1981     5000    NULL    10
1       7499    ALLEN   SALESMAN        7698    20-FEB-1981     1600    300     30

预期输出：

我想根据条件在工资栏中添加不同的金额。

a.emp_no        a.job   a.salary
7788    ANALYST 3300
7902    ANALYST 3300
7934    CLERK   1800
7566    MANAGER 3275
7839    PRESIDENT       5200
7499    SALESMAN        2100

在下面的查询中，更正下面的查询中哪里做错了

select updated_salary,result.emp_no,result.ename,case when result.salary>1000 and result.salary<=2000 then 'result.salary+500'
    when result.salary>2001 and result.salary<=4000 then 'result.salary+300' when result.salary>=4001  then 'result.salary+200' end as final_result
 from (select * from (select rank() over (partition by job order by  salary desc ) as rank,* from emp) as a where rank=1) as result;`

解决方法

尝试一下-

--Create table script
create table employee ( emp_no int,job string,salary int);

--Inserting dummy Data 
insert into employee (emp_no,job,salary) values (7788,"ANALYST",3300);
insert into employee (emp_no,salary) values (7902,3100);
insert into employee (emp_no,salary) values (7934,"CLERK",1800);
insert into employee (emp_no,salary) values (7930,1500);
insert into employee (emp_no,salary) values (7566,"MANAGER",3275);
insert into employee (emp_no,salary) values (7839,"PRESIDENT",5200);
insert into employee (emp_no,salary) values (7499,"SALESMAN",2100);

--Updated script (issue with passing the salary as string )

select salary,emp_no,case when salary>1000 and salary<=2000 then salary+500 
when salary>2001 and salary<=4000 then salary+300 
when salary>=4001  then salary+200 end as final_result 
from (select * from (select rank() over (partition by job order by  salary desc ) as rank,* from employee) as a where rank=1) as b
;
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