shiro pac4j cas如何通过jdbc身份验证获取详细的用户信息

编程问答 2022-08-11

问题描述

cas服务器是5.3.14

依赖性为：shiro-web 1.4.1，shiro-spring 1.4.1，buji-pac4j 4.1.1和pac4j-cas 3.8.3。

此网络应用是struts2 + spring

我添加了

<filter>
    <filter-name>shiroFilter</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    <init-param>
        <param-name>targetBeanName</param-name>
        <param-value>shiroFilter</param-value>
    </init-param>
</filter>
<filter>
    <filter-name>struts2</filter-name>
    <filter-class>org.apache.struts2.dispatcher.Filterdispatcher</filter-class>
  </filter>
  <filter-mapping>
    <filter-name>shiroFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

  <filter-mapping>
    <filter-name>struts2</filter-name>
    <url-pattern>/*</url-pattern>
  </filter-mapping>

到web.xml。

CasRealm扩展了Pac4jRealm：

public class CasRealm extends Pac4jRealm {

    private String clientName;    
   
    @Override
    protected AuthenticationInfo doGetAuthenticationInfo(AuthenticationToken authenticationToken) throws AuthenticationException {
        
        final Pac4jToken pac4jToken = (Pac4jToken) authenticationToken;
        final List<CommonProfile> commonProfileList = pac4jToken.getProfiles();
        final CommonProfile commonProfile = commonProfileList.get(0);
        final Pac4jPrincipal principal = new Pac4jPrincipal(commonProfileList,getPrincipalNameAttribute());
        final PrincipalCollection principalCollection = new SimplePrincipalCollection(principal,getName());        
        return new SimpleAuthenticationInfo(principalCollection,commonProfileList.hashCode());
    }
   
    @Override
    protected AuthorizationInfo doGetAuthorizationInfo(PrincipalCollection principals) {
        
        ...
    }

    public String getClientName() {
        return clientName;
    }

    public void setClientName(String clientName) {
        this.clientName = clientName;
    }
}

cas server的本地json文件是：

{
  "@class": "org.apereo.cas.services.RegexRegisteredService","serviceId": "^(http)://192.168.0.14.*","name": "local service","id": 10000003,"description": "","evaluationorder": 1
}
application.properties中的

cas server如下：

cas.authn.jdbc.query[0].url=jdbc:MysqL://localhost:3306/test
cas.authn.jdbc.query[0].user=root
cas.authn.jdbc.query[0].password=123456
cas.authn.jdbc.query[0].sql=select * from user where staff_no = ?
cas.authn.jdbc.query[0].fieldPassword=password
cas.authn.jdbc.query[0].driverClass=com.MysqL.cj.jdbc.Driver
cas.authn.jdbc.query[0].passwordEncoder.type=DEFAULT
cas.authn.jdbc.query[0].passwordEncoder.characterEncoding=UTF-8
cas.authn.jdbc.query[0].passwordEncoder.encodingalgorithm=MD5

表user包含列user_id,user_no,email,..等

我想要的是在cas服务器身份验证成功后在java code中获取详细的用户信息（例如user_id，user_no等），例如，在cas服务器身份验证成功后，它将重定向到test.action，我需要在test.action，。

中获取详细的用户信息。

我该怎么做？

解决方法

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