问题描述
这是我的列表：
prices = [
{'price': '19,294'},{'price': '20,365'},{'price': '21,437'},{'price': '22,628'},{'price': '25,963'},{'price': '26,439'},{'price': '28,821'},{'price': '29,417'},320'},797'},179'},774'},{'price': '46,686'},{'price': '47,162'},{'price': '51,807'},{'price': '52,402'}]
occupancy = [
{'occupancy': 2},{'occupancy': 2},{'occupancy': 3},{'occupancy': 4},{'occupancy': '6'},{'occupancy': '6'}]
预期结果：
results = [
{'price': '19,294','occupancy': 2},365',402','occupancy': '6'},.....]
它们具有相同的len（）和相同的阶数/范围（）
解决方法
将zip用于列表理解
例如：
prices = [{'price': '19,294'},{'price': '20,365'},{'price': '21,437'},{'price': '22,628'},{'price': '25,963'},{'price': '26,439'},{'price': '28,821'},{'price': '29,417'},{
'price': '26,320'},797'},179'},774'},{'price': '46,686'},{'price': '47,162'},{'price': '51,807'},{'price': '52,402'}]
occupancy = [{'occupancy': 2},{'occupancy': 2},{'occupancy': 3},{
'occupancy': 4},{'occupancy': 4},{'occupancy': '6'},{'occupancy': '6'}]
result = [{**m,**n} for m,n in zip(prices,occupancy)]
输出：
[{'occupancy': 2,'price': '19,{'occupancy': 2,'price': '20,'price': '21,'price': '22,{'occupancy': 3,'price': '25,'price': '26,'price': '28,'price': '29,{'occupancy': 4,{'occupancy': '6','price': '46,'price': '47,'price': '51,'price': '52,402'}]