问题描述
with t1 as (select 't1'),block1 as (
with inner1 as (
select * from t1
)
select * from inner1
),block2 as (
with b2inner1 as(
select * from block1
),b2inner2 as(
select * from block1
)
select * from b2inner2
)
select * from block2;
with t1 as (select 't1'),block1 as (
with inner1 as (
select * from t1
)
select * from inner1
)
select * from block1;
我的问题是我没有在block2子查询中使用t1,为什么查询给出了错误信息。
我认为发生错误是因为我在block2查询中两次选择了block1的结果。 dbfiddle
解决方法
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