问题描述
我有一个数据框df
,其中有四列id
,ts
,lat
和lon
。如果我在调试模式下运行df.schema()
,我会得到
0 = {StructField@13126} "StructField(id,LongType,true)"
name = "id"
dataType = {LongType$@12993} "LongType"
nullable = true
Metadata = {Metadata@13065} "{"encoding":"UTF-8"}"
1 = {StructField@13127} "StructField(ts,true)"
name = "timestamp"
dataType = {LongType$@12993} "LongType"
nullable = true
Metadata = {Metadata@13069} "{"encoding":"UTF-8"}"
2 = {StructField@13128} "StructField(lat,DoubleType,true)"
name = "position_lat"
dataType = {DoubleType$@13034} "DoubleType"
nullable = true
Metadata = {Metadata@13073} "{"encoding":"UTF-8"}"
3 = {StructField@13129} "StructField(lon,true)"
name = "position_lon"
dataType = {DoubleType$@13034} "DoubleType"
nullable = true
Metadata = {Metadata@13076} "{"encoding":"UTF-8"}"
现在,我想摆脱所有元数据,即每列的"{"encoding":"ZSTD"}"
应该被""
取代。请注意,我的实际表有很多列,因此解决方案需要有点通用。预先谢谢你!
解决方法
您可以使用encode(“ XX”,“ ignore”)
示例:
Val df=data.map(lambda x: x.encode("ascii","ignore").