问题描述
我想知道这张照片的距离（用红色绘制）。因此，这只是从外部检测到的边缘开始的一条直线。我是openCV中整个图像处理人员的新手，无法在线找到正确的解决方案，所以这就是为什么我在这里提出问题。我希望有人能帮助我。 enter image description here
解决方法
这是一种执行我在评论中建议的方法。首先对各列求和，以得到与原始图像相同的宽度，但只有一行。然后，查找第一和最后一列的总和不为零，即第一列和最后一列的颜色不是完全黑色。我修剪了您的图像-请不要张贴屏幕截图，否则算法会找到窗框！
import cv2
import numpy as np
# Load image as greyscale
im = cv2.imread('weld.png',cv2.IMREAD_GRAYSCALE)
# Sum down the columns
columnTotals = np.sum(im,axis=0)
# Now look for non-zero (non-black) entries
nz = np.nonzero(columnTotals)
# Now get left and right edges of white parts of image
left,right = nz[0][0],nz[0][-1] # (53,271)
以下是对列进行汇总时代码正在执行的直观表示：
columnTotals看起来像这样：
array([ 0,510,18870,19890,20400,19125,3060,6120,6630,6375,5610,5100,5355,7140,7395,7650,7905,4335,4590,6885,5865,4845,3570,2805,2550,2295,4080,3825,3315,1785,2040,11220,11730,11475,10965,9945,8670,0],dtype=uint64)
nz看起来像这样：
(array([ 53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100,101,102,103,104,105,106,107,108,109,110,111,112,113,114,115,116,117,118,119,120,121,122,123,124,125,126,127,128,129,130,131,132,133,134,135,136,137,138,139,140,141,142,143,144,145,146,147,148,149,150,151,152,153,154,155,156,157,158,159,160,161,162,163,164,165,166,167,168,169,170,171,172,173,174,175,176,177,178,179,180,181,182,183,184,185,186,187,188,189,190,191,192,193,194,195,196,197,198,199,200,201,202,203,204,205,206,207,208,209,210,211,212,213,214,215,216,217,218,219,220,221,222,223,224,225,226,227,228,229,230,231,232,233,234,235,236,237,238,239,240,241,242,243,244,245,246,247,248,249,250,251,252,253,254,255,256,257,258,259,260,261,262,263,264,265,266,267,268,269,270,271]),)