问题描述
我想计算一周中花费的总时间(一周的开始是从给定的日期)。
给定日期为2020-06-23 15:30:00
。下周将从7天后开始。
如果只有第二个距距第一个距不到一个小时,则活动的持续时间将通过两行相同ID的时间间隔来计算。
select t.UserName,1 + datediff(second,'2020-06-23 15:30:00',CompletedOn) / (24 * 60 * 60 * 7) as week_num,sum(datediff(minute,CompletedOn,next_ts)) as duration_minutes
from (select t.*,lead(CompletedOn) over (partition by UserName order by CompletedOn) as next_ts
from #Results t
where t.CompletedOn >= '2020-06-23 15:30:00'
) t
where datediff(minute,next_ts) < 60 and CompletedOn >='2020-06-23 15:30:00' and t.UserName = 'John B'
group by t.UserName,datediff(second,CompletedOn) / (24 * 60 * 60 * 7)
order by t.UserName,week_num;
上面的查询不考虑显示 week_num ,如果没有星期中的日期条目,则将结果显示为:
UserName | week_num | duration_minutes
---------------|----------|------------------
John B | 1 | 38
John B | 2 | 10
John B | 3 | 0
John B | 5 | 0
UserName | week_num | duration_minutes
---------------|----------|------------------
John B | 1 | 38
John B | 2 | 10
John B | 3 | 0
John B | 4 | 0
John B | 5 | 0
一些示例数据:
IF OBJECT_ID('tempdb..#Results') IS NOT NULL
Truncate TABLE #Results
else
CREATE TABLE #Results
(
UserName varchar(20) not null,CompletedOn datetime not null
)
INSERT INTO #Results (UserName,CompletedOn)
SELECT 'John B','2020-06-23T15:30:00'
INSERT INTO #Results (UserName,'2020-06-23T15:31:00'
--1 min
INSERT INTO #Results (UserName,'2020-06-30T12:57:00'
INSERT INTO #Results (UserName,'2020-06-30T13:06:00'
INSERT INTO #Results (UserName,'2020-06-30T13:34:00'
--37 min
INSERT INTO #Results (UserName,'2020-06-30 15:31:00'
INSERT INTO #Results (UserName,'2020-06-30 15:33:00'
INSERT INTO #Results (UserName,'2020-06-30 15:41:00'
INSERT INTO #Results (UserName,'2020-07-06 08:41:00'
INSERT INTO #Results (UserName,'2020-07-07 14:29:00'
INSERT INTO #Results (UserName,'2020-07-09 15:22:00'
INSERT INTO #Results (UserName,'2020-07-09 16:23:00'
INSERT INTO #Results (UserName,'2020-07-21 15:34:00'
INSERT INTO #Results (UserName,'2020-07-21 17:00:00'
INSERT INTO #Results (UserName,'2020-07-21 17:00:00'
INSERT INTO #Results (UserName,'2020-07-23 06:34:00'
INSERT INTO #Results (UserName,'2020-07-23 08:28:00'
INSERT INTO #Results (UserName,'2020-07-23 08:28:00'
解决方法
考虑加入一个recursive CTE,该匹配会生成UserName
和所有后续week_num
到定义的端点的配对。下面使用10,但可以扩展为52。
WITH pairs AS (
SELECT DISTINCT UserName,1 AS week_num
FROM #Results
UNION ALL
SELECT UserName,week_num + 1
FROM pairs
WHERE week_num < 10 -- ADJUST ## AS NEEDED
),sub AS (
SELECT t.UserName,t.CompletedOn,LEAD(CompletedOn) OVER (PARTITION BY t.UserName ORDER BY t.CompletedOn) as next_ts
FROM #Results t
WHERE t.CompletedOn >= '2020-06-23 15:30:00'
),main AS (
SELECT sub.UserName,1 + DATEDIFF(SECOND,'2020-06-23 15:30:00',sub.CompletedOn) / (24 * 60 * 60 * 7) AS week_num,SUM(DATEDIFF(MINUTE,sub.CompletedOn,sub.next_ts)) AS duration_minutes
FROM sub
WHERE DATEDIFF(MINUTE,sub.next_ts) < 60
AND sub.CompletedOn >='2020-06-23 15:30:00'
AND sub.UserName = 'John B'
GROUP BY sub.UserName,DATEDIFF(SECOND,sub.CompletedOn) / (24 * 60 * 60 * 7)
)
SELECT pairs.UserName,pairs.week_num,ISNULL(main.duration_minutes,0) AS duration_minutes
FROM pairs
LEFT JOIN main
ON pairs.UserName = main.UserName
AND pairs.week_num = main.week_num
OPTION (MAXRECURSION 0);
| | UserName | week_num | duration_minutes |
|----|----------|----------|------------------|
| 1 | John B | 1 | 38 |
| 2 | John B | 2 | 10 |
| 3 | John B | 3 | 0 |
| 4 | John B | 4 | 0 |
| 5 | John B | 5 | 0 |
| 6 | John B | 6 | 0 |
| 7 | John B | 7 | 0 |
| 8 | John B | 8 | 0 |
| 9 | John B | 9 | 0 |
| 10 | John B | 10 | 0 |