问题描述
我已经创建了一个day_of_week(dayy)函数,并在该函数中使用了switch-case语句。
function day_of_week(dayy) {
var result;
switch (dayy) {
case 1:
result = "monday";
case 2:
result = "Tuesday";
case 3:
result = "wednesday";
case 4:
result = "thursday";
case 5:
result = "friday";
case 6:
result = "saturday";
case 7:
result = "sunday";
default:
result = "No day";
}
document.write(result);
}
document.getElementById("switch").innerHTML = day_of_week(1);
document.getElementById("switch").innerHTML = day_of_week(2);
实际上,在switch-case语句中,如果没有“ break”,则代码应随机执行。但是在这里,当我声明变量称为result并为其分配大小写值而没有“ break”时。因此,代码应随机执行所有情况,而不会中断。但是,这里的变量在 重新声明该值并执行最后一种情况。 我无法知道我的错误是在声明变量还是使用switch-case语句以及所有在函数实例下。 请帮助...
解决方法
您的代码中没有break语句。我希望这对您有用。
<!DOCTYPE html>
<html>
<head>
<script>
function day_of_week(dayy){
var result;
switch(dayy){
case 1: result = "Monday";
break;
case 2: result = "Tuesday";
break;
case 3: result = "wednesday";
break;
case 4: result = "Thursday";
break;
case 5: result = "Friday";
break;
case 6: result = "Saturday";
break;
case 7: result = "Sunday";
break;
default: result = "No day";
}
document.write(result);
}
document.getElementById("switch").innerHTML = day_of_week(2);
</script>
</head>
<body>
</body>
</html>
,
我会做这样的事情来获得随机的一天:
function getDay() {
const days = ["monday","tuesday","wednesday","thursday","friday","saturday","sunday"];
return days[Math.floor(Math.random() * 7)];
}
,
我通过使用berak和Math方法来重构此代码
function day_of_week(day) {
var result;
switch (day) {
case 1:
result = "monday";
break;
case 2:
result = "Tuesday";
break;
case 3:
result = "wednesday";
break;
case 4:
result = "thursday";
break;
case 5:
result = "friday";
break;
case 6:
result = "saturday";
break;
case 7:
result = "sunday";
break;
default:
result = "No day";
}
document.write(result);
}
document.getElementById("switch").innerHTML = day_of_week(Math.floor( Math.random()*10));