问题描述
我正在使用 Django 2.2
我具有以下模型结构
class Location(models.Model):
name = models.CharField(max_length=200)
country_name = models.CharField(max_length=200)
latitude = models.FloatField(null=True,blank=True)
longitude = models.FloatField(null=True,blank=True)
class TrackingData(models.Model):
location = models.ForeignKey(Location)
我想选择纬度和相同纬度的数量
data = TrackingData.objects.filter(locaiton__latitude__isnull=False).values(latitude=F('location__latitude')).annotate(count=Count('latitude'))
我得到的结果是
<TrackingDataQuerySet [{'latitude': 28.6324823,'count': 1},{'latitude': 28.6324823,'count': 1}]>
所有纬度都是相同的,但我仍然希望得到单独的结果
<TrackingDataQuerySet [{'latitude': 28.6324823,'count': 7}]>
编辑2
print(data.query)
SELECT `tracking_location`.`latitude` AS `latitude`,COUNT(`tracking_location`.`latitude`) AS `count` FROM `tracking_trackingdata` INNER JOIN `tracking_location` ON (`tracking_trackingdata`.`location_id` = `tracking_location`.`id`) WHERE `tracking_location`.`address` IS NOT NULL GROUP BY `tracking_location`.`latitude`,`tracking_trackingdata`.`scan_time`,`tracking_trackingdata`.`created` ORDER BY `tracking_trackingdata`.`scan_time` DESC,`tracking_trackingdata`.`created` DESC
解决方法
data = TrackingData.objects.filter(locaiton__latitude__isnull=False).values(latitude=F('location__latitude').distinct()).annotate(count=Count('latitude'))