问题描述
我的字符串数组和输入内容如下
S = "Tue" and K = 23
String[] daysOfWeek = {"Mon","Tue","Wed","Thu","Fri","Sat","Sun"};
我以“ Tue”作为输入,并在10天后找到第二天。我期望答案是“星期五”
这是我的代码
String[] daysOfWeek = {"Mon","Sun"};
int day = Arrays.asList(daysOfWeek).indexOf(S);
int n = K % 7;
if((day + n) > 6) {
int index = (day + n) % 6;
//return daysOfWeek[ ];
} else {
return daysOfWeek[day + n ];
}
return null;
任何想法
解决方法
您可以使用java.time.DayOfWeek
而不是重新发明轮子。
例如:
DayOfWeek dayOfWeek = DayOfWeek.TUESDAY;
DayOfWeek dayOfWeek1 = dayOfWeek.plus(10);
System.out.println(dayOfWeek1); // FRIDAY
,
要简单!
mt<- mtcars %>% group_by(cyl,am) %>% nest() %>%
mutate(formula = "Add separate model for each row in text like mpg~wt for one row,mpg~wt+hp for another etc.")
mt$formula[[1]] <- "mpg~wt"
mt$formula[[2]] <- "mpg~wt+drat"
mt$formula[[3]] <- "mpg~wt+qsec"
mt$formula[[4]] <- "mpg~wt+gear"
mt$formula[[5]] <- "mpg~wt"
mt<- mutate(model = ?)
,
您可以对之后的天数进行模7运算,然后您可以根据输出结果找到将索引从起始位置移至结果。
,混合方法-
String[] daysOfWeek = {"Mon","Tue","Wed","Thu","Fri","Sat","Sun"};
int today = LocalDate.now().getDayOfWeek().getValue()-1;
for (int i = 0; i < 31; i++) {
System.out.println(daysOfWeek[today] + " >>> " + i + " - " + daysOfWeek[(today+i)%7]);
}