问题描述
[data-short-caption="itemName" i] .circle-base,
此选择器在DOM中标识了两个项目,我需要选择第二个项目,是否有像xpath中那样选择第二个项目的方法?
HTML结构是这样的:
<div class="selection" data-select-item="select-item">
<div data-short-caption='itemName'>
<div class=circle-base> </div>
</div>
<div data-short-caption='itemName'>
<div class=circle-base> </div>
</div>
</div>
解决方法
按照HTML:
<div class="selection" data-select-item="select-item">
<div data-short-caption='itemName'>
<div class=circle-base> </div>
</div>
<div data-short-caption='itemName'>
<div class=circle-base> </div>
</div>
</div>
要仅标识第二项,可以使用以下基于css-selectors的Locator Strategy中的任何一个:
-
使用
nth-child()
:div.selection div:nth-child(2) > div.circle-base
-
使用
nth-of-type()
:div.selection div:nth-of-type(2) > div.circle-base
如果我能正确理解您的查询,有几种方法可以通过CSS伪选择器来实现。请检查代码是否有帮助。
/*Method 1 : using last-of-type pseudo-selector*/
[data-short-caption="itemName" i]:last-of-type .circle-base{
background-color: #efefef;
}
/*Method 2 : using last-child pseudo-selector*/
[data-short-caption="itemName" i]:last-child .circle-base{
background-color: #efefef;
}
/*Method 3 : using nth-of-type pseudo-selector*/
[data-short-caption="itemName" i]:nth-of-type(2) .circle-base{
background-color: #efefef;
}
/*Method 4 : using nth-child pseudo-selector*/
[data-short-caption="itemName" i]:nth-child(2) .circle-base{
background-color: #efefef;
}
<div class="selection" data-select-item="select-item">
<div data-short-caption='itemName'>
<div class=circle-base> first child </div>
</div>
<div data-short-caption='itemName'>
<div class=circle-base> second child </div>
</div>
</div>