问题描述
公共类示例{
public static void main(String[] args) {
method();
}
public static void method()
{
try {
System.out.println("function");
throw new StaleElementReferenceException("thih sexception occured");
}
catch (StaleElementReferenceException e) {
method();
}
catch (Exception e) {
System.out.println("AssertFail");
}
}
}
如何使用Try catch避免非返回方法中的无限递归...例如下面的代码...当StaleElementException仅在我想执行“ Exception之后的函数”时发生一次,如果Stale元素在第二次出现我想让它去异常捕获并断言断言..怎么了?
解决方法
public class Sample {
public static void main(String[] args) {
method(false);
}
public static void method(boolean calledFromCatchBlock)
{
try {
System.out.println("function");
if(!calledFromCatchBlock) {
throw new StaleElementReferenceException("thih sexception occured");
} else {
throw new Exception();
}
} catch (StaleElementReferenceException e) {
method(true);
} catch (Exception e) {
System.out.println("AssertFail");
}
}
}
,
在boolean
之外引发异常(例如,method()
标志)时,应该以某种方式存储状态,检查该状态并在下次引发修改后的异常:
private static boolean alreadyThrown = false;
public static void method()
{
try {
System.out.println("function");
if (alreadyThrown) {
throw new RuntimeException("another exception occured");
} else {
alreadyThrown = true;
throw new StaleElementReferenceException("this exception occured");
}
}
catch (StaleElementReferenceException e) {
method();
}
catch (Exception e) {
System.out.println("AssertFail");
}
}
或者您可以为method(int arg)
提供一些参数,并以类似的方式检查其值:
public static void main(String[] args) {
method(1);
}
public static void method(int arg)
{
try {
System.out.println("function");
if (arg > 1) {
throw new RuntimeException("another exception occured");
} else {
throw new StaleElementReferenceException("this exception occured");
}
}
catch (StaleElementReferenceException e) {
method(arg + 1);
}
catch (Exception e) {
System.out.println("AssertFail");
}
}