注释图形中的相交点坐标python

问题描述

在代码中，我找出了两条线的交点（22,50），并希望在图形中显示（有一个箭头指向与（22,50）的交点），并想知道是否社区可以帮助我。

import matplotlib.pyplot as plt
import numpy as np
import pandas as pd
from shapely.geometry import Linestring

df = pd.read_csv("C:/Users/rajaa/Desktop/tril.csv")

t = df['time']
mu = df['material uts']
ps = df['pipe stress']

 plt.figure(figsize = (8,5),dpi = 100)

fig,ax = plt.subplots()

plt.plot(t,mu,'r',label='Material UTS')
plt.plot(t,ps,'b--',label=[enter image description here][1]'Pipe Stress as the pipe is depressurized')

plt.title('Graph 1',fontdict={'fontname': 'Arial','fontsize': 20})

plt.xticks(np.arange(0,32,2))
plt.yticks(np.arange(0,120,10))

plt.xlabel('Time (minutes)')
plt.ylabel('Pipe stress and UTS (MPa)')

plt.legend()

first_line = Linestring(np.column_stack((t,mu)))
second_line = Linestring(np.column_stack((t,ps)))
intersection = first_line.intersection(second_line) 

plt.plot(*intersection.xy,'ro')

x,y = intersection.xy


plt.show()

解决方法

ax.arrow(0,22,50,head_width=0.05,head_length=0.1,fc='k',ec='k')