无法从InputStream创建zip文件

问题描述

我需要根据输入流数据创建一个zip文件,在写入zip之前,我需要找到输入流的校验和。

为此,我正在使用以下代码:

private String writeZipFileToFS(List<ResponsePacks> attachmentList) throws IOException
    {
        File fileToWrite = new File(getZipPath() + "fileName.zip");
        try
        {
            FileUtils.copyInputStreamToFile(compress(attachmentList),fileToWrite);
        }
        catch (IOException e)
        {
            throw e;
        }
        return fileName;
    }

private InputStream compress(List<ResponsePacks> attachmentList)
    {
        byte buffer[] = new byte[2048];
        ByteArrayOutputStream byteStream = new ByteArrayOutputStream();
        ZipOutputStream zipFileToSend = new ZipOutputStream(byteStream);
        try
        {
            for (ResponsePacks info : attachmentList)
            {
                // only for successful requests files would need to be added
                zipFileToSend.putNextEntry(new ZipEntry(info.getFileName()));
                InputStream in = info.getFileContentStream();
                getCheckSum(in,info.getFileName());
                int length;
                while ((length = in.read(buffer)) >= 0)
                {
                    zipFileToSend.write(buffer,length);
                }
                zipFileToSend.closeEntry();
            }
            zipFileToSend.close();
        }
        catch (IOException e)
        {
            throw e;
        }
        return new ByteArrayInputStream(byteStream.toByteArray());
    }
    
    private static void getCheckSum(InputStream is,String fileName)
    {
        byte[] dataCopy = null;
        ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
        try
        {
            IOUtils.copy(is,outputStream);
            dataCopy = outputStream.toByteArray();
            printLog("Byte Array Size {}",dataCopy.length);
            String checkSum = calculateChecksum(dataCopy);
            printLog("Checksum for file {} {}",fileName,checkSum);
            outputStream.flush();
            outputStream.close();
        }
        catch (Exception e)
        {
            printLog("Error on calculationg checksum {}",e.getMessage());
        }
    }

    private static String calculateChecksum(byte[] dataCopy)
    {
        try (ZipInputStream zipInputStream = new ZipInputStream(new ByteArrayInputStream(dataCopy)))
        {
            ZipEntry zipEntry;
            MessageDigest digest = DigestUtils.getSha256Digest();
            DWriter writer = new DWriter(digest);
            while ((zipEntry = zipInputStream.getNextEntry()) != null)
            {
                byte[] entityData = IOUtils.toByteArray(zipInputStream);
                if (!zipEntry.isDirectory())
                {
                    writer.write(entityData);
                }
            }
            if (writer.getChecksum() != null)
            {
                return writer.getChecksum();
            }
        }
        catch (Exception e)
        {
             throw e;
        }
        return "";
    }

static class DWriter
    {
        private final MessageDigest myDigest;

        DWriter(MessageDigest digest)
        {
            myDigest = digest;
        }

        public void write(byte[] data)
        {
            myDigest.update(data);
        }

        public String getChecksum()
        {
            return new String(Hex.encodeHex(myDigest.digest()));
        }
    }

但是问题是,如果我要添加代码来计算校验和,然后使用空内容创建zip文件,如果我要删除校验和计算代码,那么将使用适当的内容创建zip文件。

enter image description here

当我检查日志时,我发现InputStream的内容也不同,但是仍然总是得到相同的checkSum(空字符串),如下所示:

Byte Array Size 20854
Checksum for file 20200910173919142.json e3b0c44298fc1c149afbf4c8996fb92427ae41e4649b934ca495991b7852b855
Byte Array Size 14383
Checksum for file 1599752440405.zip e3b0c44298fc1c149afbf4c8996fb92427ae41e4649b934ca495991b7852b855

由于哪个zip文件正在创建空白内容,而checkSum也总是创建相同的内容,所以我找不到我做错的地方。

要求帮助我找出我做错了什么地方。

解决方法

您消耗了两次相同的输入流:首先阅读它以获得校验和,然后再次阅读以写zip条目。

            getCheckSum(in,info.getFileName());
            int length;
            while ((length = in.read(buffer)) >= 0)
            {
                zipFileToSend.write(buffer,length);
            }

第二次尝试阅读时,不再需要阅读任何内容,因此没有任何内容写入zip条目。

某些输入流可以重置并读取多次,如果不是这种情况,则需要将数据保存到ByteArrayOutputStream中(就像您在getCheckSum()方法中所做的那样) ,然后您可以多次读取该数据。

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