问题描述
我是Python的新手，我正在做一些项目来尝试和学习它。我正在尝试制作剪刀石头布游戏来学习条件和循环。我的游戏中有一个名为“验证器”的函数，该函数具有一个带有4个字符串条件的while循环，但是当我尝试重新分配该变量以破坏该循环时，它仍然会显示我的错误消息，即我说“请输入有效的响应” “。
如何使while循环结束并返回变量ans？
感谢您的帮助，
乌鸦
# Rock Paper Scissors Game
import random
# Makes the Player Choose a Valid Answer Function
def validator():
ans = input()
while ans != "Rock" or "Paper" or "Scissors" or "QUIT":
ans = input("Please enter a valid response: ")
else:
return ans
# Comp Choosers Function
def compcho():
v = random.randrange(1,3)
if v == 1:
return "Rock"
if v == 2:
return "Paper"
if v == 3:
return "Scissors"
# Win decider
def decider(man,pc):
if man == pc:
return "It's a tie! " + man + " to " + pc + "!"
elif man != pc:
if man == "Rock" and pc == "Scissors":
return "The player's choice of " + man + " beats the PC's choice of " + pc + "! Player Victory!"
if man == "Rock" and pc == "Paper":
return "The player's choice of " + man + " loses to the PC's choice of " + pc + ". Player Defeat."
if man == "Scissors" and pc == "Rock":
return "The player's choice of " + man + " loses to the PC's choice of " + pc + ". Player Defeat."
if man == "Scissors" and pc == "Paper":
return "The player's choice of " + man + " beats the PC's choice of " + pc + "! Player Victory!"
if man == "Paper" and pc == "Rock":
return "The player's choice of " + man + " beats the PC's choice of " + pc + "! Player Victory!"
if man == "Paper" and pc == "Scissors":
return "The player's choice of " + man + " loses to the PC's choice of " + pc + ". Player Defeat."
if man == "Quit":
print("Goodbye")
else:
print("Hmm I wasn't expecting " + man + ".")
# Program Start
print("Welcome to the Rock Paper Scissors Game!")
choice = "ham"
while choice != "Quit":
# Chooser
print("Please Enter Rock Paper Scissors or Quit")
valans = validator()
pcpick = compcho()
print(decider(valans,pcpick))
解决方法
欢迎您！写一个结构良好的问题做得很好。
您在这里遇到的问题与条件表达式的计算方式有关。您现在拥有的方式，Python正在执行此操作：
while (ans != "Rock") or ("Paper") or ("Scissors") or ("QUIT")
在这种情况下，字符串“ Paper”，“ Scissors”和“ Quit”本身始终为true。您可以在这里看到它：
>>> bool("Rock")
True
您想要的是：
while ans not in ["Rock","Paper","Scissors","QUIT"]:
您需要让其中一个函数返回值"Quit"并为其设置变量choice。我现在不在我的个人计算机上，所以我将主要回答您的代码。.也许以后我会回去编辑一些清理得更多的东西。
# Rock Paper Scissors Game
import random
# Makes the Player Choose a Valid Answer Function
def validator():
ans = input()
while ans != "Rock" or "Paper" or "Scissors" or "QUIT":
ans = input("Please enter a valid response: ")
else:
return ans
# Comp Choosers Function
def compcho():
v = random.randrange(1,3)
if v == 1:
return "Rock"
if v == 2:
return "Paper"
if v == 3:
return "Scissors"
# Win decider
def decider(man,pc):
if man == pc:
return "It's a tie! " + man + " to " + pc + "!"
elif man != pc:
if man == "Rock" and pc == "Scissors":
return "The player's choice of " + man + " beats the PC's choice of " + pc + "! Player Victory!"
if man == "Rock" and pc == "Paper":
return "The player's choice of " + man + " loses to the PC's choice of " + pc + ". Player Defeat."
if man == "Scissors" and pc == "Rock":
return "The player's choice of " + man + " loses to the PC's choice of " + pc + ". Player Defeat."
if man == "Scissors" and pc == "Paper":
return "The player's choice of " + man + " beats the PC's choice of " + pc + "! Player Victory!"
if man == "Paper" and pc == "Rock":
return "The player's choice of " + man + " beats the PC's choice of " + pc + "! Player Victory!"
if man == "Paper" and pc == "Scissors":
return "The player's choice of " + man + " loses to the PC's choice of " + pc + ". Player Defeat."
if man == "Quit":
print("Goodbye")
# Must return a value here...
return "Quit"
else:
print("Hmm I wasn't expecting " + man + ".")
# doesn't matter what gets returned here based on your other code so lets return "Keep Playing" for consistency
return "Keep Playing"
# Program Start
print("Welcome to the Rock Paper Scissors Game!")
choice = "ham"
while choice != "Quit":
# Chooser
print("Please Enter Rock Paper Scissors or Quit")
valans = validator()
pcpick = compcho()
choice = decider(valans,pcpick) # see we set choice to the value of the decided function.
print(choice)
# now the loop will have a condition that will cause it to exit.
您可以这样编写条件（重复变量名称并检查逻辑运算符）：
while ans != "Rock" and ans != "Paper" and ans != "Scissors" and ans != "QUIT":
或使用'in'：
while ans not in ["Rock","QUIT"] :