问题描述
我正在python中使用turtle来创建简单的形状,这些形状的渐变从白色开始到黑色结束,黑色为0,0。我目前设置的方式是,它将在嵌套循环中继续减去零。我希望我的代码在颜色等于或小于0,0时将其打印为黑色。如果有人可以给我指示和提示而又不直接给我解决方案,我将不胜感激。谢谢!
a = int(input("Enter int angle:"))
q = int(input("Enter int length:"))
print("Click turtle screen to exit...")
r=1
g=1
b=1
import turtle
wn = turtle.Screen()
wn.bgcolor("white")
alex = turtle.Turtle()
alex.speed(500)
alex.pencolor("white")
for i in range (q):
alex.forward(i)
alex.left(a)
for c in range (q):
alex.pencolor(r,g,b)
r=(r-.0001)
g=(g-.0001)
b=(b-.0001)
wn.exitonclick()
解决方法
在您的最终for循环中,您应该拥有
for c in range (q):
alex.pencolor(r,g,b)
if condition (color is black or less than black):
result (print black)
else:
r=(r-.0001)
g=(g-.0001)
b=(b-.0001)
,
如果我们在迭代次数上使颜色递减1,那么在上一次迭代中颜色应达到黑色:
from turtle import Screen,Turtle
screen = Screen()
angle = screen.numinput("Angle","Enter angle: ",default=110,minval=1,maxval=359)
length = int(screen.numinput("Length","Enter integer length: ",default=75,minval=10,maxval=200))
gray = 1.0
turtle = Turtle()
turtle.speed('fastest')
for _ in range(length):
turtle.pencolor(gray,gray,gray)
turtle.forward(length)
turtle.left(angle)
gray = gray - 1.0 / length
screen.exitonclick()
但是,如果那仍然给您带来问题,则可以将其包装在max()
中:
gray = max(0,gray - 1.0 / length)