问题描述
尝试使用qualify row_Number()和Qualify Min&Max函数,但仍无法获取交易日期范围。请参阅下面的数据结构
需要以下输出的帮助
提前谢谢
解决方法
您需要先找到连续日期的组。有几种方法可以做到这一点,对于您而言,最好的方法是将一个序列与另一个有缺口的序列进行比较:
with cte as
(
select t.*
-- consecutive numbers = sequence without gaps,row_number()
over (partition by location,cust#,cust_type -- ??
order by transaction_date) as rn
-- consecutive numbers as long as there's no missing date = sequence with gaps,(transaction_date - date '0001-01-01') as rn2
-- assign a common (but meaningless) value to consecutive dates,-- value changes when there's a gap,rn2 - rn as grp
from tab as t
)
select location,cust_type -- ??,min(transaction_date),max(transaction_date),min(amount),max(amount)
from cte
-- add the calculated "grp" to GROUP BY
group by location,cust_type,grp
用于PARTITION BY / GROUP BY的列取决于您的规则。