当数量在ajax中变化时，如何更改总价？

问题描述

我使用了jquery的append函数将值转移到另一端。所以我附加了输入类型号，该值自动等于1。

是否要增加输入类型数字的值的问题，如果我增加数字的值，价格如何翻倍？

刀片

@foreach($service->invoices as $invoice)
    <tr>
        <td class="text-right">{{ $invoice->description }}</td>
        <td>
            <div class="custom-control custom-checkbox">
                <input type="checkbox" class="custom-control-input" name="custom{{ $invoice->id }}" id="custom{{ $invoice->id }}">
                <label class="custom-control-label" for="custom{{ $invoice->id }}"></label>
            </div>
        </td>
        <td>
            <div class="form-row justify-content-center">
                <div class="form-group mb-0">
                    <div class="input-group mx-auto mb-0">
                        <div class="number-input amount">
                            <button onclick="this.parentNode.querySelector('input[type=number]').stepDown()" id="decrease"></button>
                            <input class="quantity bg-light" id="quantity" min="0" placeholder="0" name="quantity" value="0" type="number">
                            <button onclick="this.parentNode.querySelector('input[type=number]').stepUp()" class="plus" id="increment"></button>
                        </div>
                    </div>
                </div>
            </div>
        </td>
        <td class="cost">{{ $invoice->price }}
        <td class="total"></td>
    </tr>
@endforeach

script.js

<script>
    $('.amount > input[type="number"]').on('input',updateTotal);

    function updateTotal(e){
        var amount = parseInt(e.target.value);

        if (!amount || amount < 0)
            return;

        var $parentRow = $(e.target).parent().parent();
        var cost = parseFloat($parentRow.find('.cost').text());
        var total = (cost * amount).toFixed(2);

        $parentRow.find('.total').text(total);
    }
</script>

css

input[type="number"] {
    -webkit-appearance: textfield;
    -moz-appearance: textfield;
    appearance: textfield;
}

input[type=number]::-webkit-inner-spin-button,input[type=number]::-webkit-outer-spin-button {
    -webkit-appearance: none;
}

.number-input {
    border: 2px solid #ddd;
    display: inline-flex;
}

.number-input,.number-input * {
    box-sizing: border-box;
}

.number-input button {
    outline:none;
    -webkit-appearance: none;
    background-color: transparent;
    border: none;
    align-items: center;
    justify-content: center;
    width: 3rem;
    height: 3rem;
    cursor: pointer;
    margin: 0;
    position: relative;
}

.number-input button:before,.number-input button:after {
    display: inline-block;
    position: absolute;
    content: '';
    width: 1rem;
    height: 2px;
    background-color: #212121;
    transform: translate(-50%,-50%);
}
.number-input button.plus:after {
    transform: translate(-50%,-50%) rotate(90deg);
}

.number-input input[type=number] {
    font-family: sans-serif;
    max-width: 5rem;
    padding: .5rem;
    border: solid #ddd;
    border-width: 0 2px;
    text-align: center;
}

我的输入号码是这样的。

解决方法

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