问题描述
我想使用symfony / http-client测试来自API的不同响应,但是如何创建statusCode 400?
这是我尝试过的:
public static function mockShipmentResponseFail(): MockResponse
{
$body = [
'HttpStatusCode' => 400,'HttpStatusDescription' => 'Bad Request','Message' => 'One or more shipments are invalid','Errors' => [
'Message' => 'The first line of the address must be 35 characters or less.','Cause' => 'DestinationAddressLine1','ErrorCode' => 'E1433',//Invalid field
'ErrorId' => '932478fg83r7gf'
]
];
return new MockResponse([json_encode($body)],['http_code' => 400]);
}
并像这样使用它:
$responses = [CourierServiceTest::mockLoginResponse(),CourierServiceTest::mockShipmentResponseFail()];
$mockClient = new MockHttpClient($responses);
$someService = new SomeService($mockClient,$request->server);
$apiResponse = $someService->orders($tmpOrder1->getId());
$responseArray = json_decode($apiResponse->getContent(),true);
$this->assertEquals(400,$apiResponse->getStatusCode());
$this->assertJson($apiResponse->getContent());
很遗憾,我收到以下错误消息:
Symfony \ Component \ HttpClient \ Exception \ ClientException:HTTP 400 返回“ https://api.someservice.net/api/”。
try {
$apiResponse = $this->client->request('POST',$url,[
'headers' => [
'accept' => 'application/json','content-type' => 'application/json',other headers
],'body' => [
$body
]
]);
} catch (ClientException $exception) {
return $exception->getResponse();
}
解决方法
因此,您正在创建一个返回错误400的函数,然后您在调用该函数时始终会收到HTTP 400错误,对吗?
我不明白您想要实现什么,请您澄清一下吗?
,我编辑了问题,但我意识到getContent()和toArray()会抛出ClientException,而request()不会,因此无法捕获
,这就是我所做的:
$body = '{"data": 1}';
// create the mock response
$client = new MockHttpClient([new MockResponse(
$body,[
'response_headers' => ['content-type' => 'application/json'],'http_code' => 400
]
)]);
// do the request
$response = $client->request('GET',$url);
// assert the content
$this->assertEquals(
$body,$response->toArray(false)
);