将数据从一个表连接到另一个表

问题描述

我想将表1中的数据合并到表2中

表1

id        grp_name
-----------------------------
1       A@erf,[e-mail]
2       [e-mail],[e-mail]/[e-mail]
3       [e-mail],[e-mail],[e-mail]
4       [e-mail]#[e-mail]
5       [e-mail]

表2

code       name
-----------------------------------
1        [e-mail],[e-mail]
2        [e-mail]
3        [e-mail]
4        [e-mail]
5        [e-mail]
6        [e-mail]

我想使用逗号（'，'）将grp_name数据与名称数据（例如concanate）连接起来 grp_name数据中有不需要的符号，例如“＃”，“ /”，我也希望消除这些符号。

我创建了以下步骤，但我不知道我是否有效。 如果仅使用简单的update语句或merge语句是可能的，请告诉我。

例外结果

code       name
1        [e-mail],[e-mail],A@erf,[e-mail]
2        [e-mail],[e-mail],[e-mail],[e-mail]
3        [e-mail],[e-mail],[e-mail]
4        [e-mail],[e-mail],[e-mail]
5        [e-mail],[e-mail]
6        [e-mail]

CREATE OR REPLACE PROCEDURE procedure1
AS

    CURSOR cur
    IS
    SELECT id,grp_name
    FROM TABLE 1;
    
    CURSOR cur2
    IS
    SELECT code,name
    FROM TABLE 2;
    
      v_a       VARCHAR2(300);
 v_b       VARCHAR2(25);
 v_c    VARCHAR2(4000);
 v_d       VARCHAR2(250);

BEGIN

    FOR i IN cur
    LOOP
        v_a := ','||i.grp_name;
        v_b := i.id;
        
        FOR e IN cur2
        LOOP
            v_c := e.name || v_a ;
            v_d := i.code;
        
    
        UPDATE schema_name.TABLE 2
        SET name = v_c
        WHERE v_d = v_b;
        
        END LOOP;
    END LOOP;
    
--  COMMIT;
END;

解决方法

在最简单的情况下，例如@jarlh所说，您可以进行更新：

update table2
    set name = name 
            || (select ',' || regexp_replace(grp_name,'[/#]',',') -- replace / and # with,from table1
                where table1.id = table2.code)
where code in (select id from table1); -- only update matching rows

最后一行不是严格必要的，但是最好避免不必要的更新。

如果TABLE1中还有要添加的表2中不匹配的行，请使用插入符：

insert into table2 (code,name)
    select id,regexp_replace(grp_name,')
    from table1
    where id not in (select code from table2);

编辑：就像戈登提到的那样，如果您这样存储数据，则使用SQL的时间会更短：

code       name
1        [e-mail]
1        [e-mail]
1        A@erf
1        [e-mail]
2        [e-mail]
2        [e-mail]
2        [e-mail]
2        [e-mail]
3        [e-mail]
3        [e-mail]
3        [e-mail]
3        [e-mail]

,

请尝试以下操作：

With tab1 as
(
select 1 as id,'A@er#f,[e-mail]' as grp_name from dual union all
select 2 as id,'[e-mail],[e-mail]#g/[e-mail]' as grp_name from dual
),tab2 as (
select 1 as id,'[e-mail],[e-mail]' as name from dual union all
select 2 as id,'[e-mail]' as name from dual
)
select REGEXP_REPLACE (grp_name||','||name,'[^a-zA-Z0-9|\@|\,]','') as name from tab1 inner join tab2 using(id);

结果：

A@erf,R@erfin,A@weot,D@refas
B@goin,D@storgS@recuy,B@dein